Ask question

Ask question

All categories

Thepotemich [5.8K]

4 years ago

13

1.Sobre a queda-livre,assinale V para verdadeiro e F para falso

1 answer:

lisov135 [29]4 years ago

8 0

Answer:pelo o que eu sei é ..

V

V

V

F

F

F

Explanation:

You might be interested in

An electromagnetic radio wave is received by a transmitter before it is converted to a sound wave. The radio wave has a waveleng

lakkis [162]

Answer: The velocity is the wave traveling at before the transmitter converts it to a sound wave is $2.99\times 10^8 m/s$

Explanation:

Wavelength of the electromagnetic wave = 23,076 m

Frequency of the wave = 13,000 Hertz

$\text{Time period}=\frac{1}{Frequency}$

$Velocity=\frac{displacement}{Time}=\frac{\lambda}{\text{Time period}}=\lambda \times Frequency=23,076\times 13,000 Hertz=2.99\times 10^8 m/s$

The velocity is the wave traveling at before the transmitter converts it to a sound wave is $2.99\times 10^8 m/s$

8 0

3 years ago

Read 2 more answers

What is the equation for frequency?

timofeeve [1]

Answer:

f=1/t is the equation of frqency

8 0

3 years ago

Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out

PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is

$\lambda _2 = (6.48,6.52) \ cm$

Explanation:

From the question we are told that

The wavelength of the note is $\lambda = 6.50 \ cm = 0.065 \ m$

The difference in beat frequency is $\Delta f = 17.0 \ Hz$

Generally the frequency of the note played by the guitar that is in tune is

$f_1 = \frac{v_s}{\lambda}$

Where $v_s$ is the speed of sound with a constant value $v_s = 343 \ m/s$

$f_1 = \frac{343}{0.0065}$

$f_1 = 5276.9 \ Hz$

The difference in beat is mathematically represented as

$\Delta f = |f_1 - f_2|$

Where $f_2$ is the frequency of the sound from the out of tune guitar

$f_2 =f_1 \pm \Delta f$

substituting values

$f_2 =f_1 + \Delta f$

$f_2 = 5276.9 + 17.0$

$f_2 = 5293.9 \ Hz$

The wavelength for this frequency is

$\lambda_2 = \frac{343 }{5293.9}$

$\lambda_2 = 0.0648 \ m$

$\lambda_2 = 6.48 \ cm$

For the second value of the second frequency

$f_2 = f_1 - \Delta f$

$f_2 = 5276.9 -17$

$f_2 = 5259.9 Hz$

The wavelength for this frequency is

$\lambda _2 = \frac{343}{5259.9}$

$\lambda _2 = 0.0652 \ m$

$\lambda _2 = 6.52 \ cm$

8 0

3 years ago

Jenny and Betty are having a great time at Busch Gardens riding the Ubanga Banga bumper cars. Jenny, who is traveling southward

lutik1710 [3]

They both exert an equal amount of force onto each other

7 0

4 years ago

Newton's second law of motion states the relationship of mass, acceleration and force. It states that

sergey [27]

Answer:

C

Explanation:

force equals mass time acceleration

5 0

3 years ago