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3 years ago

Will give brainliest

Physics

1 answer:

NNADVOKAT [17]3 years ago

5 0

I love science! if you need any more help let me know i cant guarantee i can help but i will try!

The correct answer is "Some substances must be dissolved in water before they can be used".

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Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes

scoundrel [369]

Answer:

The appropriate solution is "0.597 mm".

Explanation:

Given that:

Wavelength,

$\lambda = 519 \ nm$

or,

$=519\times 10^{-9}$

Distance,

$D=4.6 \ m$

Separated by,

$\beta = 4.0 \ mm$

or,

$=4.0\times 10^{-3}$

As we know,

⇒ $\beta=\frac{\lambda D}{d}$

or,

The separation of two slits will be:

⇒ $d=\frac{\lambda D}{\beta}$

By putting the values, we get

$=\frac{(519\times 10^{-9})(4.6)}{4.0\times 10^{-3}}$

$=5.97\times 10^{-4}$

or,

$=0.597 \ mm$

8 0

3 years ago

Imagine that a brown horse and a white horse cross to produce offspring whose coat is made up of some brown hair and some white

Fantom [35]

This is an example of Co dominance.

4 0

3 years ago

Read 2 more answers

A car slow down at -5.00 m/s2 until it comes to a stop after traveling 15.0 m. What was the initial speed of the car? (Unit=m/s)

vlabodo [156]

Good formula to remember!

V_F^2 = V_0^2 + 2 * a * d

V_F = final speed
V_0 = initial speed

0^2 = V_0^2 + 2*(-5)*15 = V_0^2 -150,

V_0 = sqrt(150) = 12.25 m/s

7 0

3 years ago

Read 2 more answers

Calculate the escape velocity

o-na [289]

Answer:

v = 2.38 × 10³ m/s

Explanation:

Escape velocity, v = √(2gR) where g = acceleration due to gravity on planet and R = radius of planet.

Since it is given that the weight of the man on the moon is 1/6 his weight on earth, and g' = acceleration due to gravity on moon and g = acceleration due to gravity on earth and m = mass of man,

mg' = mg/6

g' = g/6

Since g = 9.8 m/s²,

g'= 9.8 m/s² ÷ 6

g' = 1.63 m/s²

The escape velocity of the moon is thus v = √(2g'R) where R = radius of moon = 1.737 × 10⁶ m.

Substituting these into v, we have

v = √(2g'R)

v = √(2 × 1.63 m/s² × 1.737 × 10⁶ m)

v = √[5.663 × 10⁶ (m/s)²]

v = 2.38 × 10³ m/s

8 0