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MrMuchimi
2 years ago
5

If the Universe was born at the Big Bang, what existed before then?​

Physics
1 answer:
Aleonysh [2.5K]2 years ago
8 0
<h2>Answer:</h2>

<em>Hey, </em>

<h3><u>QUESTION)</u></h3>

This is a complicated question that would be debated by many physicists. How to answer this question when we are struggling with the genesis of the universe? Many theories on the origin of the universe have been put forward, but the Bing Bang is probably, or at least to date, the most likely theory. If today the universe is expanding, some astronomers hypothesise that before the Bing Bang the universe already existed but that it was condensing, according to this hypothesis the Bing Bang would correspond to the limit point of compression of the universe.  

But if we remain in the traditional theory the Bing Bang is at the origin of all the matter we know, as well as light. Before the Bing Bang, in other words before the universe, there was NOTHING.

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A deuteron (a nucleus that consists of one proton and one neutron) is accelerated through a 4.01 kV potential difference. How mu
Nonamiya [84]

Complete Question:

A deuteron (a nucleus that consists of one proton and one neutron) is accelerated through a 4.01 kV potential difference. b) How much kinetic energy does it gain? The mass of a proton is 1.67262 × 10−27 kg, the mass of a neutron 1.67493 × 10−27 kg and the charge on an electron −1.60218 × 10−19 C. Answer in units of J\

b) what is the speed?

Answer:

a) the kinetic energy gained =  6.42 * 10⁻¹⁶ J

b) the speed of the particle, v = 619328.3 m/s

Explanation:

q = 1.602 *10⁻¹⁹C

V = 4.01 kV  = 4.01 * 10³ V

Work done by the deuteron = qV

Work done by the deuteron = 1.602 * 10⁻¹⁹ *  4.01 *10³

Work done = 6.42 * 10⁻¹⁶ J

Kinetic Energy gained = work done

Kinetic Energy gained by the deuteron =  6.42 * 10⁻¹⁶ J

B) The formula for Kinetic Energy is given by:

KE = 1/2 Mv²

Let the mass of the proton be m₁ = 1.67262 × 10⁻²⁷kg

Let the mass of the neutron be m₂ =   1.67493 × 10−27 kg

M = m₁ + m₂

KE = 1/2 ( m₁ + m₂)v²

Let v = speed of the deuteron

From part (a)

KE = 6.42 * 10⁻¹⁶ J

 1/2 ( m₁ + m₂)v²=  6.42 * 10⁻¹⁶

0.5 * (1.67262 + 1.6749) *10⁻²⁷ * v² =  6.42 * 10⁻¹⁶

v = 619328.3 m/s

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3 years ago
A cruise ship is having troubles with buoyancy. What is a reasonable solution? A. Increase the weight of the ship above water B.
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If a cruise ship is having troubles with buoyancy, then spread the weight of the ship over a greater volume.

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<u>Explanation: </u>

Buoyancy is the upward thrusting phenomenon of water acting on any object immersed partially or fully in water body. Hence, it creates the buoyant forces that is inversely proportionate to the immersing body's density. If the immersing body's density is higher than the density of the immersing medium then the body will get completely immersed in the water.

Similarly, in case of less, the buoyant forces act on the body will prevent it from complete immersion and allow it to float on water. Mostly cruise ships and other navy vessels use this phenomenon to keep on floating on surface of water.

In the present condition, the solution for buoyancy problem faced by a cruise ship can be solved by decreasing the density of the ship. And the ship's density can be decreased by increasing the ship's volume or by spreading the ship's weight over a greater volume.

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Answer:

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8 0
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