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3 years ago

If the Universe was born at the Big Bang, what existed before then?

Physics

1 answer:

Aleonysh [2.5K]3 years ago

8 0

<h2>Answer:</h2>

<h3><u>QUESTION)</u></h3>

This is a complicated question that would be debated by many physicists. How to answer this question when we are struggling with the genesis of the universe? Many theories on the origin of the universe have been put forward, but the Bing Bang is probably, or at least to date, the most likely theory. If today the universe is expanding, some astronomers hypothesise that before the Bing Bang the universe already existed but that it was condensing, according to this hypothesis the Bing Bang would correspond to the limit point of compression of the universe.

But if we remain in the traditional theory the Bing Bang is at the origin of all the matter we know, as well as light. Before the Bing Bang, in other words before the universe, there was NOTHING.

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Many fitness programs include weight training, which A. can be used in place of aerobic exercise, when done regularly. B. helps

11Alexandr11 [23.1K]

The answer would be C) because weight lifting is used to increase your muscular strength, and that's why you try and add more weight during sessions, so it's not too easy for you and you can build a higher endurance.

6 0

3 years ago

A spaceship accelerates uniformly for 1220km how much time is needed for the spaceship to increase its speed from 11.1km/s to 11

snow_lady [41]

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s

<h3>Data obtained from the question</h3>

The following data were obtained from the question given above:

Initial velocity (u) = 11.1 Km/s
Final velocity (v) = 11.7 Km/s
Distance (s) = 1220 Km
Time (t) =?

<h3>How to determine the time</h3>

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:

s = (u + v)t / 2

Cross multiply

(u + v)t = 2s

Divide both sides by (u + v)

t = 2s / (u + v)t

t = (2 × 1220) / (11.1 + 11.7)

t = 2440 / 22.8

t = 107 s

Thus, the time taken for the spaceship to change its speed is 107 s

Learn more about speed:

brainly.com/question/680492

Learn more about velocity:

brainly.com/question/3411682

#SPJ1

6 0

1 year ago

Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially

statuscvo [17]

Answer:

Final speed is 900.06 m/s at $0.2215^{\circ}$

Solution:

As per the question:

Mass of the first asteroid, m = $15\times 10^{3}\kg$

Mass of the second asteroid, m' = $20\times 10^{3}\kg$

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, $\theta = 20^{\circ}$

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

$\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}$

Thus applying vector addition and momentum conservation, the final velocity is given by:

$(m + m')v_{final} = \sqrt{(mv)^{2} + 2(mv)(m'v')cos20^{\circ} + (m'v')^{2}}$ (1)

Now,

$(m +m')v_{final} = (35\times 10^{3})v_{final}$

$(mv)^{2} = (15\times 10^{3}\times 770)^{2} = 1.334\times 10^{14}$

$(m'v')^{2} = (20\times 10^{3}\times 1020)^{2} = 4.16\times 10^{14}$

$2(mv)(m'v')cos20^{\circ} = 2(15\times 10^{3}\times 770)(20\times 10^{3}\times 1020)cos20^{\circ} = 4.43\times 10^{14}$

Now, substituting the suitable values in eqn (1), we get:

$v_{final} = 900.06\ m/s$

Now, the direction for the two vectors is given by:

$\theta = sin^{- 1} \frac{m'v'sin20^{\circ}}{(m + m')v_{final}}$

$\theta = sin^{- 1} \frac{20\times 10^{3}\times 1020sin20^{\circ}}{(35\times 10^{3})\times 900.06} = 0.2215^{\circ}$

5 0

3 years ago

A ball rolls down a hill and hits a box. The momentum of the ball decreases. Which happens to the momentum? Select one of the op

Irina-Kira [14]

<span>So we want to know what happens to the momentum of the ball that rolls down hill and hits a box. So we need to use the law of conservation of momentum which states that the momentum must be conserved. It cant be transformed into inertia or mass. It can only be transferred to other object via some interactions like collisions. So it has to be a. transferred to the box and that is the correct answer. </span>

7 0

3 years ago

Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia

melisa1 [442]

Answer:

$H_2 = 91.55 km$