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GenaCL600 [577]
4 years ago
9

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Physics
1 answer:
azamat4 years ago
7 0

Answer:

1.After 11 hours, the cruise ship will be  _233.75__nautical miles from the lighthouse.

2.At the start of the journey, the cruise ship was _10.5__ nautical miles from the lighthouse.

3.The cruise ship is traveling at a speed of_21.25_  nautical miles per hour.

Explanation:

Distance covered in 2 hours= 95.5-53NM

=42.5NM

therefore,

Speed= Distance/time................(1)

put value of distance and time in equation (1)

therefore,

speed= 42.5/2hour

speed=21.25NM/hour

Therefore distance covered in 11 hours= speed* time

Distance=21.25*11

=233.75NM

2. Since distance covered in 2 hours is 42.5

therefore, at starting of the journey the cruise distance from light house is

= 53NM-42.5NM

=10.5NM

3. Distance covered in 2 hours= 95.5-53NM

=42.5NM

therefore,

Speed= Distance/time................(1)

put value of distance and time in equation (1)

therefore,

speed= 42.5/2hour

speed=21.25NM/hour

Therefore Cruise ship is traveling at speed of 21.25NM/hour

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The string constrains the rotational and translational motion of the falling cylinder, given that it doesn't slip. what is the r
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<span>Answer: First we need to find the acceleration. torque on cylinder τ = T * r where T is the string tension; T = m(g - a) where a is the acceleration of the cylinder. Then τ = m(g - a)r But also τ = Iα. For a solid cylinder, I = ½mr², and if the string doesn't slip, then α = a / r, so τ = ½mr² * a/r = ½mra. Since τ = τ, we have m(g - a)r = ½mra → m, r cancel, leaving g - a = ½a g = 3a/2 a = 2g/3 where g, of course, is gravitational acceleration. We know that v(t) = a*t, so for our cylinder v(t) = 2gt / 3 ◄ linear velocity and ω = v(t) / r = 2gt / 3r ◄ angular velocity</span>
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A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. id
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Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as opposing forces pull it.

The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

A horizontally pulling rope is dragging a box across the floor at a consistent speed. Friction is significant.

Hence, the force acting on the box will be weight W,  Normal force N, and the tension force T, in the string.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

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