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barxatty [35]
2 years ago
13

A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. id

entify all the forces acting on the box.
Physics
1 answer:
Elena-2011 [213]2 years ago
8 0

Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as opposing forces pull it.

The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

A horizontally pulling rope is dragging a box across the floor at a consistent speed. Friction is significant.

Hence, the force acting on the box will be weight W,  Normal force N, and the tension force T, in the string.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

#SPJ1

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Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

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We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
3 years ago
A cylinder of mass 250 kg and radius 2.60 m is rotating at 4.00 rad/s on a frictionless.
aleksandrvk [35]

Answer:

The angular momentum of a cylinder, when it is rotating with constant angular velocity is Lini =Iωi

. When two cylinders are added to the rotating cylinder, which are identical in their dimensions, the moment of inertia of the entire system increases (since mass increases). The final moment of inertia will be 3I

Since friction exist, all the cylinders start rotating with same angular velocity, the new angular velocity can be calculated using conservation of angular momentum

Thus, Iωi =3Iωf ⟹ωf =ωi/3 = 0.33ωi

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3 years ago
Calcular la rapidez promedio
Vlada [557]

Answer:

  v_average = 15 m / s

Explanation:

The average speed can be found in two ways,

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* taking the velocities in each time interval and then finding the weighted average by the time fraction

              v_average = 1 / t_total ∑  v_{i}  t_{i}vi ti

Let's apply this last equation

               

Total time is

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              v_average = 10/20 10 + 10/20 20

              v_average = 10/2 + 20/2

              v_average = 15 m / s

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A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a
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4 of
Maksim231197 [3]

Answer:

all of the above????

Explanation:

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