<u>Explanation:</u>
s = ? u = 0m/s v = ? a = 5m/s² t = 2s
v = u + at
= 0 + (5 x 2)
= 10 m/s
s = ut + 1/2 at²
= (0)(2) + x x 5 x 2²
= 10 m
Hope this helps!
A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. id
1 answer:
Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.
<h3>What is tension force?</h3>The tension force is described as the force transferred through a rope, string, or wire as opposing forces pull it.
The tension force is applied along the whole length of the wire, pulling energy equally on both ends.
A horizontally pulling rope is dragging a box across the floor at a consistent speed. Friction is significant.
Hence, the force acting on the box will be weight W, Normal force N, and the tension force T, in the string.
To learn more about the tension force refer to the link;
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Answer: Option (b) is the correct answer.
Explanation:
It is given that a positive test charge q is released from rest at a distance r away from a charge of +Q and a distance 2r which is away from a charge of +2Q.
Then test charge to the right immediately after being released.
Therefore, the net force will be as follows.
F =
=
=
F = > 0
Thus, we can conclude that the test charge move to the right immediately after being released.