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Likurg_2 [28]
3 years ago
12

A 610-N hiker carrying an 11.0-kg backpack hiked up a trail for 23 minutes. At the end of that time, he is 150 m higher than whe

n he started. (a) How much the the backpack weigh? (b) How much work is accomplished to carry the backpack that distance? (c) How much total work is accomplished? (Use the total weight: hiker + backpack.) (d) What is the hiker’s power in watts? (Don’t forget to convert 23 minutes to seconds.)
Physics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

a)110 N (assuming g = 10 m/s2 )

b) 16500 J

c) ≅ 11.96 W

Explanation:

a) 150 m is not enough to a sensible change of gravitational acceleration at that level from Earth's surface. Therefore, backback weight is same as when it is in ground level.

W = mg, W = weight of object ; m = mass of the object ; g =  gravitational acceleration felt by object.

By substituting,

W = 11×10 = 110 N (assuming g = 10 m/s2 )

b)  Work done = Energy change

    Work done by lifting the bag = Potential energy change

                                                     = mgh ; h = Vertical height lifted

                                                     = 11×150×10 (assuming g = 10 m/s2 )

                                                     = 16500 J

c) Power = Work done/ time taken

               = 16500/(23×60)                (minutes converted to seconds by multiplying by 60)

               ≅ 11.96 W

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Answer:

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