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Serga [27]
3 years ago
7

Which of the following is a risk associated with the application of biotechnology?

Physics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

d.) potential for the exchange of genetic material

Explanation:

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A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an
navik [9.2K]

The statements that are true are;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J
<h3>What is work done?</h3>

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J

Learn more about work: brainly.com/question/18094932?

4 0
2 years ago
Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note
love history [14]

Answer:

The energy is 9.4\times10^{-21}\ J

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

Q=\Delta U+W

Q=\Delta U+nRT

Put the value into the formula

4480=\Delta U+\dfrac{20}{28}\times8.314\times77

\Delta U=4480-\dfrac{20}{28}\times8.314\times77

\Delta U=4022.73\ J

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

N=n\times \text{Avogadro number}

Put the value into the formula

N=\dfrac{20}{28}\times6.02\times10^{23}

N=4.3\times10^{23}

We need to calculate the energy

Using formula of energy

E=\dfrac{\Delta U}{N}

Put the value into the formula

E=\dfrac{4022.73}{4.3\times10^{23}}

E=9.4\times10^{-21}\ J

Hence, The energy is 9.4\times10^{-21}\ J

4 0
3 years ago
In which situation is work being done?
Keith_Richards [23]

Answer: D. The force and displacement are in the same direction.

Explanation:

The Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path with distance d.  

Work is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy).

Now, when the applied force is constant and the direction of the force and the direction of the displacement are <u>parallel</u>, the equation to calculate it is:  

W=(F)(d) (1)

When they are not parallel, both directions form an angle, let's call it \alpha. In that case the expression to calculate the Work is:  

W=Fdcos{\alpha} (2)

When the force and displacement are perpendicular to each other,\alpha=90\° and <u>no work is done</u>.

4 0
3 years ago
A U.S. Department of Energy report estimates that over 100 billion kWh/year can be saved in the United States by various energy-
I am Lyosha [343]

Answer:

(a). 12 plants

(b). 3171 $

Explanation:

(a)first convert units of 100 billion kWh/year into Watts(W)

also convert the units of 1000 MW into Watts(W)

1 billion = 10^9

1 year = 365*24 = 8760 hrs

so

100 billion kWh/year = 1\frac{100*(10^9)*(10^3)}{8760}

                                  = 1.142*10^{10}W

1000 MW                  = 1000*10^{6} = 10^{9}W

no. of plants = \frac{1.14155*10^{10} }{10^9} = 11.4

So 12 plants required        

(b)

savings = unit price*total units

             = 0.1 * 1.142*10^{10}( \frac{1}{1000*3600} )

             = 3170.9 =3171 $

4 0
3 years ago
Read 2 more answers
A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
Pie

Answer:

0.128 s

Explanation:

We have to start by calculating the net force acting on the log. We have two forces:

- The constant pulling force, forward, of F = 2500 N

- The frictional force, backward

The frictional force is given by

F_f = \mu mg

where

\mu=0.45 is the coefficient of friction

m = 300 kg is the mass of the log

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_f = (0.45)(300)(9.8)=1323 N

So the net force acting on the log is

F=2500 - 1323=1177 N

Now, we can find the acceleration of the log by using Newton's second law

F=ma

where a is the acceleration. Re-arranging for a,

a=\frac{F}{m}=\frac{1177}{300}=3.92 m/s^2

And finally we can find the time it takes for the log to reach a speed of

v = 0.5 m/s

by using the suvat equation:

v=u+at

where u = 0 is the initial speed and t the time. Solving for t,

t=\frac{v}{a}=\frac{0.5}{3.92}=0.128 s

5 0
4 years ago
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