Answer:
a) Number of generating plants N = 11.42
That means N > 11
N = 12
b) annual savings S = $1×10^10
S = $10 billion
Explanation:
Given;
Amount of energy to be saved A=100 billion kWh/year
Capacity of each generating plant C= 1000 MW
Rate in dollars of cost of electricity R= $0.10/kWh
The number N of generating plants with capacity C that can supply the Amount A of of energy cam be given as;
N = A/C ......1
And also the Annual savings S in dollars if the rate of electricity cost R is used and amount of energy A is saved is:
S = AR .....2
But we need to derive the value of A in Watts
A = 100 billion kWh/year
There are 8760hours in a year,
A = 1×10^14 ÷ 8760 W
A = 11415525114.1W or 11415525.1141kW
C = 1000MW = 1× 10^9 W
a) Using equation 1,
N = 11415525114.1/(1×10^9)
N = 11.42
That means N > 11
N = 12
b) using equation 2
S = 1×10^11 kWh × $0.10/kWh
S = $1×10^10
S = $10 billion