Answer:
4 mol of Al₂O₃ are produced from 8 mole of Al
Explanation:
The reaction:
4 Al + 3O₂ → 2Al₂O₃
Ratio is 4:2
So, If we have 8 mol of Al, we will produce 4 mol of Al₂O₃
Electronic structure refers to the way atoms are organized according to electron shell theory. It tells us what energy level the electrons are in and the number of electrons per energy level.
The groups of the periodic table are classified according to the valence electrons, that is, the electrons that they have in their last energy level. These electrons can make an atom more or less reactive. For example, an element in the last period, period 8. It has 8 valence electrons, that is, it complies with the octet rule and these atoms are very stable. Therefore, its reactivity is very low compared to other groups.
Groups 1 and 7 are quite reactive since group 1 has an electron in the last energy level. So it only has to lose one electron to form a bond and react. Group 7 has 7 electrons in its last energy level, that is, it needs 1 electron to form a bond. In general, group 7 elements are very reactive with group 1 elements.
So the main difference in group reactivity will be the valence electrons.
First, we have to get moles of CH3COONa = mass/molar mass
= 20 g / 82.03 g/mol = 0.244 moles
when we have [CH3COOH] = 0.15 M
∴ [CH3COONa] = moles of CH3COONa / Volume of solution
= 0.244 moles / 0.5L = 0.488 M
when we look up for Ka of acetic acid value it is equal 1.8 x 10^-5
So we can get Pka = -㏒Ka
= -㏒(1.8 x10^-5)
= 4.7
now we will use Henderson - Hasselbalchn equation to get the PH:
PH = Pka + ㏒[conjugate basic/weak acid]
when CH3COOH is the weak acid & CH3COO- is the conjugate base so by substitution:
PH = 4.7 + ㏒ (0.488/0.15)
= 5.2
b) when we have this equation for the reaction:
HCl + CH3COONa → CH3COOH + NaCl
ionic equation : H+ + Cl- + CH3COO- + Na+ → CH3COOH + Na+ + Cl-
when HCl + H2O → H3O+ + Cl-
∴ the reaction will be:
CH3COO- (aq) + H3O+(aq) → CH3COOH(aq) + H2O(l)
<span>The wick merely transports some of the liquid up to where vaporizes.It is not part of reaction but it does affect the reaction rate greatly,so it is a sort of catalyst in that time.if you wrap the wick in the aluminum it will block the transport the wax and it will wither go out less or brightly</span>
Answer:
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Explanation: