What is the specific heat of a substance if 300 J are required to raise the temperature of a 267-g sample by 12 degrees Celsius? Please show all work! Thanks!
1 answer:
The specific heat capacity of a substance if 300 j are required to raise the temperature of 207 g by 12 degrees is calculated using the formula below Q=Mc deltaT Q(heat required) = 300 j M(mass) =207g c(specific heat capacity) = ? delta t(change in temperature)= 12 c by making c the subject of the formula C= Q/ M delta T C= 300 j/ 267 g x 12 c = 0.0936 j/g/c
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