What is the specific heat of a substance if 300 J are required to raise the temperature of a 267-g sample by 12 degrees Celsius?
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Answer:
Explanation:
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In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:
Whereas solving for the final temperature T2, we get:
Thus, we plug in the given data (temperature in Kelvins) to obtain:
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