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4 years ago

Select the single best answer. Determine the following type of reaction: CH3―CH2―CH(Br)―CH3 CH3―CH═CH―CH3 + NaBr + H2O

Chemistry

1 answer:

Setler79 [48]4 years ago

3 0

Answer:

Deshydrohalogenation

Explanation:

You are not providing options to answer, however, this can be answered without options.

Now, in the reaction we can see that we have an atom of Bromine in carbon 2, and in the product appears as NaBr. This means that the Br was substracted by elimination. It's an elimination because the final product do not have a substituent where the bromine was, (Like another nucleophyle such OH or another halide). If you look closely the final product, we can see that one hydrogen in carbon 3, is no longer there. So this electrophyle was also substracted, in this case, by a base (Such NaOH), so in this case, it's ocurring an elimination reaction via E2 (One step, bimolecular). So, as the final product has been substracted the nucleophyle and electrophyle, this treaction is a deshydrohalogenation (an atom of hydrogen and a halide were substracted). The mechanism of this, you can see it in the picture.

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3 years ago

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3 years ago

3S8 + 8 OH- + 8 S3 + 4 HOOH

NemiM [27]

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied. So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

2^1 = 2^1

The order of reaction with respect to [OH^-] = 1

So we have the overall rate law as;

Rate = k[S8]^1 [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

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3 years ago

Predict the electron pair geometry and the molecular structure of each of the following molecules or ions: (a) ClNO (N is the ce

S_A_V [24]

Answer:

See explanation

Explanation:

In ClNO , nitrogen is the central atom here. The central atom has a tetrahedral electron pair geometry and a lone pair on the nitrogen atom. Due to the lone pair, the electron pair geometry is now trigonal pyramidal.

The molecule CS2 has a linear molecular geometry. There are four electron groups around the central atom hence the electron pair geometry is tetrahedral but the molecular geometry results from the repulsion of the two double bonds.

The electron domain geometry for Cl2CO is tetrahedral since there are four electron pairs around the central atom. However, the molecular geometry is trigonal planar due to the sp2 hybridization of the central carbon atom.

The electron domain geometry of Cl2SO is tetrahedral due to the four electron pairs around the central atom. However, due to the lone pair on sulphur, the molecular geometry is triagonal pyramidal.

In SO2F2, sulphur the central atom is surrounded by four electron pairs which are all bonding groups hence both the molecular geometry and the electron pair geometry is tetrahedral.

In XeO2F2, the central atom is Xe. There are five electron pairs around the Xe central atom four of which are bonding groups. The electron domain geometry and molecular geometry is trigonal bipyramidal.

For ClOF2 , the central atom Cl is surrounded by four electron pairs hence the electron pair geometry is tetrahedral but it is an AX3E(three bonding groups and one lone pair are present in the structure) specie hence it is trigonal pyramidal.

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3 years ago

The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for t

kotykmax [81]

Answer:

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

$\displaystyle 3\text{H$_2$} + \text{N$_2$} \longrightarrow 2\text{NH$_3$}$

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

$\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \\ \\ & = 0.102\text{ g H$_2$}\end{aligned}$

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

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3 years ago