1.5 What is the purpose of adding sodium carbonate to the reaction mixture? I

1 answer:

7 0

Answer: As sodium carbonate is added, bubbles of carbon dioxide form. When all the acid has been neutralised, adding sodium carbonate will no longer produce bubbles of carbon dioxide gas. The final rinsing with water should remove traces of the water soluble salt formed.

Explanation:

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Summarize at least three steps needed to carry out Galileo's famous experiment to determine whether heavier objects

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According to legend, Galileo dropped weights off of the Leaning Tower of Pisa, showing that gravity causes objects of different masses to fall with the same acceleration. In recent years, researchers have taken to replicating this test in a way that the Italian scientist probably never envisioned — by dropping atoms. One of Galileo's contributions to the founding of modern science was his study of falling objects. He turned, then, to measuring the acceleration of objects rolling down smooth ramps. The ramp "diluted" the acceleration to a value small enough to allow accurate measurements of the longer time intervals.

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Brad and Matt are working in the lab. They noticed that when they mixed two dilute solutions together, the reaction between them

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An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:

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2,4,4-trimethyl-2-pentene yields mixture of $(CH_{3})_{2}C=O$ and $(CH_{3})_{3}CHO$

Explanation:

In ozonolysis (hydrolysis step involve a reducing agent such as Zn, $Me_{2}S$ etc.), a pi bond is broken to form ketone/aldehyde.

Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of $(CH_{3})_{2}C=O$ and $(CH_{3})_{3}CHO$

Reaction steps are shown below.

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