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Zanzabum
3 years ago
7

Help pls! 10 points!!

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

A. The perimeter of the original figure is multiplied by 3 ,and the area is multiplied by 9.

(9=3²)

it is a rule in the dilation course:

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The volume of a cube is 27n^27 cubic units. What is the length of one side of the cube?
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The volume of a cube (V) is given in terms of its side length (s) as

... V = s³

You have

... 27n²⁷ = s³

You may recognize that 27 = 3³, so this can be written as

3^3\cdot n^{3\cdot 9} = \left(3n^{9}\right)^{3}=s^{3}\\\\3n^{9}=s\qquad\mbox{taking cube roots}

This result matches your second selection

... 3n⁹ units

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The measure of angle θ is 600°. <br> The point (x, y) corresponding to θ on the unit circle is (
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by 3




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6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi
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Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of p = 1 - 0.85 = 0.15

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

So

P = 0.15P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597

So

P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390

3.90% probability that the third failure will occur on the tenth component tested

5 0
3 years ago
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