Answer: current is 8.0 A
Explanation: R= U/I I = U/R = 120 V/15 Ω= 8.0 A
Answer:
26.67 s
Explanation:
v = Velocidad final = 40 m/s
u = Velocidad inicial = 20 m/s
= Tiempo inicial = 20 s
= Tiempo empleado durante la aceleración
a = Aceleración
s = Desplazamiento del automóvil durante la aceleración = 200 m
De las ecuaciones lineales de movimiento tenemos


El tiempo necesario para acelerar es 6.67 s
El tiempo total necesario para toda la ruta es
.
Answer:
Explanation:
Given that, .
R = 12 ohms
C = 500μf.
Time t =? When the charge reaches 99.99% of maximum
The charge on a RC circuit is given as
A discharging circuit
Q = Qo•exp(-t/RC)
Where RC is the time constant
τ = RC = 12 × 500 ×10^-6
τ = 0.006 sec
The maximum charge is Qo,
Therefore Q = 99.99% of Qo
Then, Q = 99.99/100 × Qo
Q = 0.9999Qo
So, substituting this into the equation above
Q = Qo•exp(-t/RC)
0.9999Qo = Qo•exp(-t / 0.006)
Divide both side by Qo
0.9999 = exp(-t / 0.006)
Take In of both sodes
In(0.9999) = In(exp(-t / 0.006))
-1 × 10^-4 = -t / 0.006
t = -1 × 10^-4 × - 0.006
t = 6 × 10^-7 second
So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge
Answer:
Spin a coil of wire inside a magnetic field or move a magnet inside a coil of wire.
Explanation:
This is according to Faraday's law of electromagnetic induction.