Work done by a constant force equal the magnitude of that is force multiplied by what?
1 answer:
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Answer:
52.5°C
Explanation:
The final enthalpy is determined from energy balance where initial enthalpy and specific volume are obtained from A-12 for the given pressure and state
mh1 + W = mh2
h2 = h1 + W/m
h1 + Wα1/V1
242.9 kJ/kg + 2.35.0.11049kJ/ 0.35/60kg
=287.4 kJ/kg
From the final enthalpy and pressure the final temperature is obtained A-13 using interpolation
i.e T2 = T1 + T2 -T1/h2 -h1(h2 - h1)
= 50°C + 60 - 50/295.15 - 284.79
(287.4 - 284.79)°C
= 52.5°C
The new acceleration is c) 18m/s/s
Explanation:
Net force, mass and acceleration of an object are related by Newton's second law of motion:
where
F is the net force on the object
m is its mass
a is its acceleration
In the first trial of this problem, a net force of is applied to the object, causing an acceleration of
Calling the mass of the object 'm', this means that
[N] (1)
In the second trial, the force applied is , so we have
where a' is the new acceleration. Substituting (1) into the second equation, we find:
This is because the acceleration is directly proportional to the force applied: therefore, if the force applied doubled, the acceleration doubles as well.
Learn more about Newton's second law:
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