<em>A straight piece of wire with a current I flowing through it is placed in a magnetic field</em>
<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the string</em>
<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the stringthere is a way</em>
Take a look at the picture. The speed of the connected cars is 1/4 of the single car’s speed, and the kinetic energy is 1/4 of the single car’s kinetic energy
To solve this problem we will proceed to use the equations given for the calculation of the resistance, in order to find the radius of the cable. Once the length is found we can find the number of turns of the solenoid and finally the net length of it
The resistance of the wire is
= Resistivity
L = Length
A = Cross-sectional Area
That can be also expressed as,
Rearranging the equation for the length of the wire we have
The number of turns of the solenoid is
Denominator is equal to the circumference of the loop
Finally the Length of he solenoid is
Where \phi is the diameter of wire
Therefore the length of the solenoid is 7.532m
Answer:
The x-coordinate of the particle is 24 m.
Explanation:
In order to obtain the x-coordinate of the particle, you have to apply the equations for Two Dimension Motion
Xf=Xo+Voxt+0.5axt²(I)
Yf=Yo+Voyt+0.5ayt² (II)
Where Xo, Yo are the initial positions, Xf and Yf are the final positions, Vox and Voy are the initial velocities, ax and ay are the accerelations in x and y directions, t is the time.
The particle starts from rest from the origin, therefore:
Vox=Voy=0
Xo=Yo=0
Replacing Yf=12, Yo=0 and Voy=0 in (I) and solving for t:
12=0+(0)t+ 0.5(1.0)t²
12=0.5t²
Dividing by 0.5 and extracting thr squareroot both sides:
t=√12/0.5
t=√24 = 2√6
Replacing t=2√6, ax=2.0,Xo=0 and Vox=0 in (I) to obain the x-coordinate:
Xf=0+0t+0.5(2.0)(2√6)²
Xf= 24 m
