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Andrews [41]
3 years ago
13

How long would it take to drive to the moon at 100 mph?

Physics
1 answer:
inysia [295]3 years ago
6 0
Distance to the moon: 238,900 miles

238,900 divided by 100= 2389 hrs

2389 hrs divided 24 hrs= 99.5 Days

Given you could “drive” to the moon, it would take about 100 days
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dsp73

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t    = power X time

W / t = P   power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec  = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c)  E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

5 0
3 years ago
If the baseball and the plastic ball were moving at the same speed which ball would hit a bat harder
Lerok [7]
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4 years ago
The angular momentum of an electron in each of its orbits must be some multiple of:
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The Bohr's proposal for the angular momentum of an electron in Bohr's model of the hydrogen atom is:

L=(n*h)/(2π), where n is the number of the energy level and h is the Planck's constant. This equation shows us the quantization of angular momentum of the electron. So the correct answer is the second one: Planck's constant. 
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3 years ago
A ball is rolling across the floor at a constant speed. What will happen to the ball if it is exposed
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7 0
3 years ago
Read 2 more answers
In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
Alina [70]

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
4 years ago
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