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Tema [17]
3 years ago
13

Atoms of two different elements must have different____

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
8 0

Answer:

Atomic numbers

Explanation:

Atoms of two different elements must have different <u>atomic</u><u> </u><u>numbers</u><u>.</u><u> </u>

Lelu [443]3 years ago
7 0
Atomic number
Atoms of different elements must have different atomic number. The atomic number of each element is different than other Elements.
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Point of incidence: The point on the surface where the incident ray strikes the surface is called the point of incidence. Reflected ray: The ray of light that bounces back from the surface of an object is called a reflected ray of light.

Explanation:

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Question 13 of 32
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Answer:

A

Explanation:

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3 0
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Why is our mindset more important when you try to learn remotely than when you are learning face to face?
Marrrta [24]

Answer:

It is more important because of the freedom.

Explanation:

While at home you can do your work of course... but you could lay down, take a nap. You could get on the game, play around. You could draw, and fiddle and dance and do WHATEVER you want with no teacher to stop you so you have to be your own motivation. You have to be your own teacher or its VERY easy to fail.

5 0
3 years ago
Which notation represents atoms that have the same number of protons but a different neutron?
ArbitrLikvidat [17]
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5 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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