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Ostrovityanka [42]
2 years ago
12

which drawing below represents the electric field surrounding two objects that have equal magnitude changes of opposite polarity

? ​

Physics
1 answer:
Fantom [35]2 years ago
8 0

Answer:

the 3rd one

Explanation:

j cause I think so

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A rat is pushed with a massive force. The mass of the rat is 2.3 kg and the acceleration of the rat is 9.5 m/s^2. What was the f
Phoenix [80]

Answer:

Force = 21.85N

Explanation:

Given the following data;

Mass = 2.3kg

Acceleration = 9.5m/s²

To find the force;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Substituting into the equation, we have

Force = 2.3 * 9.5

Force = 21.85N

Therefore, the force applied to the rat is 21.85 Newton.

8 0
3 years ago
I will mark as the brainliest answer​
erastova [34]

Answer:

8) 1500 feet

9) 20 miles

10) 4 Days

11) 2250 miles

12) 1 hour and 5 minutes

13) 27.27miles per hour

Explanation

8) There are 60 seconds in one minute so 60x25=1500 feet

9) 30 minutes is half of an hour so 40 miles ÷ 2 = 20 miles

10) 12x4=48

11) 500 miles x 4.5 hours is 2250 miles

12) Train leaves at 3pm after 60 miles it will be 4 pm and after 5 more miles 4:05 pm so 1 hour and 5 minutes

13)

Elmo = 40 minutes and 5 miles

Bert and Ernie = 45 minutes and 15 miles

Cookie Monster = 20 minutes and 10 miles

Home = 5 minutes abd 20 miles

Average Speed including stops is 27.27 miles per hour

5 0
3 years ago
Please helppppp asapppp
yuradex [85]
The picture won’t load
5 0
2 years ago
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

#SPJ10

8 0
1 year ago
In which situation does heating a substance generally change the temperature?
marta [7]
The correct answer is C
5 0
3 years ago
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