A heliocentric system is a sun-centered
Answer:
The appropriate solution is "2.78 mm".
Explanation:
Given:
or,
or,
As we know,
Fringe width is:
⇒ 
hence,
Separation between second and third bright fringes will be:
⇒ 
or,
44 x 12. I got the 12 from the total of 12 months in a year.
44 > 40
x
12 > 10
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The way my teacher taught me how to estimate is look at the neighbor to 44 and 12. The only time 44 can become 50, is when the neighbor is 5 or up. Same thing for 12. Now, multiply 40 and 10.
40 x 10 = 400.
Therefore, your estimate is 400.
The real answer is 520 breaths.
<span>AS T1,T2,T3 are the tensions in the ropes,assuming that there are Three blocks of mass 3m, 2m, and m.T3 is the string between 3m and 2m,T2 is the string between 2m and m ,T1 is the string attached to m thus T1 pulls the whole set of blocks along, so it must be the largest. T2 pulls the last
two masses, but T3 only pulls the last mass, so T3 < T2 < T1.</span>
