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Eddi Din [679]
3 years ago
9

Someone please quickly help me with this problem?

Physics
2 answers:
Crazy boy [7]3 years ago
5 0
The answer is 60 km. I hope it helps i dont know if this is right or wrong.
Thepotemich [5.8K]3 years ago
4 0
The answer should be 56 I believe you just do 70x4 then divide by the hours tins took
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A boy takes hold of a rope to pull a wagon (m = 50 kg) on a surface with a static coefficient of friction μS = 0.25. Calculate t
vivado [14]

Answer:

<em>The force that would be applied on the rope just to start moving the wagon is 122 N</em>

Explanation:

Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction  opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move  can be calculated using equation 1.

F = μ x mg .............................. 1

where F is the frictional force;

          μ is the coefficient of friction ( μs, in this case, static friction);

          m  is mass of the object and;

          g is the acceleration due to gravity( a constant equal to 9.81 m/s^{2})

from the equation we are provide with;

       μs  = 0.25

       m = 50 kg

       g =  9.81 m/s^{2}

      F =?

Using equation 1

F = 0.25 x 50 kg x  9.81 m/s^{2}

F = 122.63 N  

<em>Therefore a force of 122 N must be applied to the rope just to start the wagon.</em>

6 0
4 years ago
Read 2 more answers
Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acc
GREYUIT [131]
The total force applied by the three people is:
F=30 N+20 N+10 N=60 N
This force is pushing toward the direction of the motion, while the  frictional force F_f points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
F-F_f = ma
We know the mass of the block, m=500 kg, and the acceleration, a=0.02 m/s^2, so we can find the friction:
F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N
8 0
4 years ago
Who participates in sport more? women or men and why?
Katen [24]
More women ...........I'm not sure why
6 0
4 years ago
Read 2 more answers
Why is aluminum suitable material to use in makinv cans based on its physical and chemical properties
Llana [10]

low density, malleable, easy to form into shapes, not very chem reactive

7 0
3 years ago
g 2. In a laboratory experiment on standing waves a string 3.0 ft long is attached to the prong of an electrically driven tuning
abruzzese [7]

Answer:

The tension in string will be "3.62 N".

Explanation:

The given values are:

Length of string:

l = 3 ft

or,

 = 0.9144 m

frequency,

f = 60 Hz

Weight,

= 0.096 lb

or,

= 0.0435 kgm/s²

Now,

The mass will be:

= \frac{0.0435}{9.8}

= 0.0044 \ kg

As we know,

⇒  \lambda=\frac{2L}{n}

On substituting the values, we get

⇒     =\frac{2\times 0.9144}{4}

⇒     =0.4572 \ m

or,

⇒  v=f \lambda

⇒      =0.4572\times 60

⇒      =27.432 \ m/s

Now,

⇒  v=\sqrt{\frac{T}{\mu} }

or,

⇒  T=\frac{m}{l}\times v^2

On putting the above given values, we get

⇒      =\frac{0.0044}{0.9144}\times (27.432)^2

⇒      =\frac{752.51\times 0.0044}{0.9144}

⇒      =3.62 \ N

7 0
3 years ago
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