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Kaylis [27]
1 year ago
9

4.

Chemistry
1 answer:
Naya [18.7K]1 year ago
5 0

For all the reactions listed, the moles of products and limiting reactants are;

1. Molar cofficient - 6, oxygen is the limiting reactant

2. Molar coefficient - 8 chlorine is the limiting reactant

3. Molar coefficient - 4 and CO2 is the limiting reactant

<h3>What is a chemical reaction?</h3>

A chemical reaction is a combination of reactants that yields products. Recall that the limiting reactant is the reactant that nis present in the least amount.

Let us now complete each reaction;

1. The molar coefficient of the product in reaction 1 is 6 and oxygen is the limiting reactant

2. The molar For all the reactions listed coefficent of the product in reaction 2 is 8 and chlorine is the limiting reactant

3. The molar coefficient of the product in reaction 3 is 4 and the limiting reactant is CO2.

Learn more about limiting reactant: brainly.com/question/14225536

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Calculate the volume of chlorine molecules produced at room temperature and pressure, when 234g of sodium chloride are electroly
rewona [7]

The volume of chlorine molecules produced at STP would be 96 dm³.

<h3>Stoichiometric problem</h3>

Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:

NaCl --- > Na^+ + Cl^-

This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.

Recall that: mole = mass/molar mass

Hence, 234 g of sodium chloride will give:

                         234/58.44 = 4.00 moles.

Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.

Recall that:

1 mole of every gas at Standard Temperature and Pressure = 24 Liters.

Hence:

4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

4 0
1 year ago
Write the formulae for the following and calculate the molecular mass for each one of them,
tatuchka [14]

Explanation:

a) NaHCO₃

= 23 + 1 + 12 + 16×3

= 23 + 1 + 12 + 48

= 84 g/mol

b) CaO

= 40 + 16

= 56 g/mol

c) NaCl

= 23 + 35.5

= 58.5 g/mol

8 0
3 years ago
MM H2O2 = 34.02 g/mol MM H2O = 18.02 g/mol MM O2 = 32 g/mol
Kaylis [27]

  The grams   of oxygen that  are   produced  is  228.8 grams


  <em>calculation</em>

2H₂O₂ → 2H₂O +O₂

Step 1:  use  the  mole ratio to determine the moles of O₂

from equation above H₂O₂:O₂  is   2:1

therefore the  moles of O₂  = 14.3 moles ×1/2 = 7.15   moles

Step 2:  find  mass   of O₂

mass = moles ×  molar mass

= 7.15 moles × 32 g/mol =228.8 g

3 0
3 years ago
A)Completaţi ecuaţiile chimice următoare cu formulele chimice şi coeficienţii adecvaţi:
Scilla [17]

Answer:co2

Explanation:because of the oxygen levels

6 0
3 years ago
Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
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