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Dimas [21]
3 years ago
14

A rod of mass M = 4 kg, length L = 1.8 meters, and moment of inertia ML2/12 is free to move on a frictionless surface. The rod i

s at rest when a puck of mass m = 0.4 kg approaches with a speed vi = 20 m/s perpendicular to the rod's length and strikes the rod at a point d = 0.3 meters from its lower end. After the collision, the puck moves backward with a speed vf = 10 m/s. The rod's center of mass moves forward with speed v and rotates with angular speed ω. (a) What is the speed v of the rod's center of mass after the collision?
Physics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

The speed of the rod's center of mass after the collision is 6 m/s.

Explanation:

Given that,

Mass of rod = 4 kg

Length l = 1.8 m

Moment of inertia I=\dfrac{ML^2}{12}

Mass of puck = 0.4 kg

Initial speed= 20 m/s

Distance = 0.3 m

Final speed = 10 m/s

(a). We need to calculate the speed v of the rod's center of mass after the collision

As there is no external force acting on the system so, linear and angular momentum of the system will be conserved.

Using conservation of momentum

m_{i}v_{i}=m_{f}v_{f}+Mv

Put the value into the formula

0.4\times20=-0.4\times10+2v

v=\dfrac{8+4}{2}

v=6\ m/s

Hence, The speed of the rod's center of mass after the collision is 6 m/s.

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Momentum is conserved when carts are collided on a slanting plane.

To find the answer, we need to know about the conversation of momentum.

<h3>What's the conversation of momentum?</h3>
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Explanation:

a) The tractor has not toppled over because the vertical line from the center of gravity to the ground is still in between the wheel base such that since the tractor will topple over by turning clockwise about the right tire due to its weight, the weight of the tractor is currently acting in the anticlockwise direction to the right end tire of the tractor keeping the tractor's tires in good contact with the ground

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b) When the upper deck is full of passengers, there will be an appreciable proportion of the total mass of the bus in the upper deck such that the level of the center of mass will be raised up higher

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