All categories

3 years ago

When price increases, quantity supplied:

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

It should increase but I’m between stays the same or increase, I’m not sure in a 100% sorry...

You might be interested in

Solve the system of equations:<br> y = 2x - 3<br> y = x2 - 3

Tamiku [17]

Answer:

(0, -3), (2, 1)

Step-by-step explanation:

Solve this by solving for the first variable in one of the equations, then substitute the result into the other equation.

5 0

3 years ago

True [87]

Answer:

D. RWS and SWT

Step-by-step explanation:

Adjacent angles have a common side and a common vertex but they don't overlaps each other

The two angles that has these requirements are :

RWS and SWT

8 0

2 years ago

Read 2 more answers

6197 divided by 93 long division answer pls ASAP

Kazeer [188]

Answer:

Step-by-step explanation:

66.6344086

3 0

1 year ago

Read 2 more answers

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

pogonyaev

$Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested$

$Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)$

$Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)$

$\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)$

$Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250$

$\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250$

5 0

3 years ago

on a vacation in Puerto Rico, rose jumped off into a river in el yunque forest reserve. her height as a function of time could b

hoa [83]

The main assumption here is that the height at the water level is 0.

So, the answer is given by the solution to the equation

- 16t^2 + 16t + 480 = 0

To solve it, start dividing by -16 to get:

t^2 - t - 30 = 0.

Now factor the left side:

(t - ) (t + ) =0

Find two numbers that add - 1 and its product is -30

(t - 6 ) (t + 5 ) =0

That gives:

t - 6 = 0 ⇒ t = 6 seconds

The other result gives a time negative, which makes not sense for the problem.

Verify substituing 6 in the original equation:

h(6) = -16*6^2 + 16*6 + 480 = -576 + 96 + 480 = 0. Lo cual confirma nuestra solucion.

It toke Rose 6 seconds to hit the water.

7 0

3 years ago