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3 years ago

12

Which of the following conditions will drive the equilibrium of the Fischer esterification towards ester formation? A) addition

of water B) removal of water as it is formed C) addition of an inorganic acid as a catalyst D) addition of alcohol E) both B and D

1 answer:

Lana71 [14]3 years ago

7 0

Both B and D I thinks soo

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3.) If Lebron James has a vertical leap of +1.35 m. then what is his takeoff speed7 For this

Scilla [17]

D, I hoped that helped you

7 0

4 years ago

Read 2 more answers

Light traveling through plate glass (n = 1.52) approaches the surface, i.e. the air-glass interface. What minimum incident angle

Ilia_Sergeevich [38]

Answer:

41°

Explanation:

refractive index of glass, n = 1.52

For total internal reflection, the angle of refraction in rarer medium is 90°.

r = 90°

Let the angle of refraction in denser medium, that means in glass is i.

By use of Snell's law

refractive index of rarer medium with respect to denser medium, that means refractive index of air with respect to glass = 1 / n

And

$\frac{1}{n}=\frac{Sin i}{Sin r}$

$\frac{1}{1.52}=\frac{Sin i}{Sin 90}$

$0.658= Sin i$

i = 41°

Thus, the angle of incidence should be 41°.

8 0

3 years ago

The average marathon runner can complete the 42.2-km distance of the marathon in 3 h and 30 min. If the runner's mass is 85 kg,

Semenov [28]

Answer:

the runner's average kinetic energy during the run is 476.96 J.

Explanation:

Given;

mass of the runner, m = 85 kg

distance covered by the runner, d = 42.2 km = 42,200 m

time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)

= 12,600 s

The speed of the runner, v = d/t

v = 42,200 / 12,600

v = 3.35 m/s

The runner's average kinetic energy during the run is calculated as;

K.E = ¹/₂mv²

K.E = ¹/₂ × 85 × (3.35)²

K.E = 476.96 J

Therefore, the runner's average kinetic energy during the run is 476.96 J.

5 0

3 years ago

The maximum potential energy of a spring system (mass 15 kg, spring constant 850 N/m) is 6.5 J. a) What is the amplitude of the

Bumek [7]

Answer:

a) 0.124 m

b) 0.93 ms⁻¹

c) 0.5 k A² cos ² ( ωt )

Explanation:

1) Potential energy = U = 0.5 k A² , where A is the amplitude and k = 850 N/m is the spring constant.

0.5 ( 850) (A² ) = 6.5

⇒ A = 0.124 m = Amplitude.

b) From energy conservation, 0.5 m v² = 6.5

⇒ speed = v = 0.93 ms⁻¹

c) If x = A cos ωt ,

Potential energy = 0.5 k A² = 0.5 k A² cos ² ( ωt )

8 0

3 years ago

When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting,

ad-work [718]

Answer:

EMF = 11.35 V

R = 0.031Ω

Explanation:

To find the battery's EMF and the internal resistance we need to use Ohm's law:

$V = IR$

Where:

V: is the voltage

I: is the current

R is the resistance

We have:

The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:

$\epsilon = V + IR$

$\epsilon = 9.36 V + 64.2A*R$ (1)

When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:

$\epsilon = 11.3 V + 1.96A*R$ (2)

By solving equation (1) and (2) for R we have:

$9.36 V + 64.2A*R = 11.3 V + 1.96A*R$

$R = \frac{1.94 V}{62.24A} = 0.031 \Omega$

Hence, the internal resistance is 0.031 Ω.

Now, by entering R into equation (1) we can find the battery's EMF:

$\epsilon = 9.36 V + 64.2A*0.031 \Omega$

$\epsilon = 11.35 V$

Therefore, the battery's EMF is 11.35 V.

I hope it helps you!

8 0

4 years ago