consider the west direction as positive direction of motion
V' = velocity of airplane relative to observer on ground = 580 mph
v = velocity of wind relative to observer on ground
V = average speed of airplane with no wind = 600 mph
relative velocity is given as
V' = V + v
inserting the values
580 = 600 + v
v = 580 - 600
v = - 20 mph
the negative sign indicates the direction of wind is opposite to direction of airplane , east
hence speed of wind is 20 mph in east direction.
Answer:
53.06°
Explanation:
refractive index of air = 1
refractive index of water, n = 1.33
Let the angle of polarisation is ip.
Use Brewster's law,
n = tan ip
1.33 = tan ip
ip = 53.06°
thus, the angle of polarisation is 53.06°.
Answer:
The angle of the incline above horizontal is 17.81 degrees.
Explanation:
Given that,
Mass of the object, m = 4 kg
Acceleration of the object above the incline, 
We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :
So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.
Answer:
the <em>ratio F1/F2 = 1/2</em>
the <em>ratio a1/a2 = 1</em>
Explanation:
The force that both satellites experience is:
F1 = G M_e m1 / r² and
F2 = G M_e m2 / r²
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- r is the orbital radius
- M_e is the mass of Earth
Therefore,
F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]
F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]
F1/F2 = m1/m2
F1/F2 = 1000/2000
<em>F1/F2 = 1/2</em>
The other force that the two satellites experience is the centripetal force. Therefore,
F1c = m1 v² / r and
F2c = m2 v² / r
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- v is the orbital velocity
- r is the orbital velocity
Thus,
a1 = v² / r ⇒ v² = r a1 and
a2 = v² / r ⇒ v² = r a2
Therefore,
F1c = m1 a1 r / r = m1 a1
F2c = m2 a2 r / r = m2 a2
In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,
F1 = F1c
G M_e m1 / r² = m1 a1
a1 = G M_e / r²
also
a2 = G M_e / r²
Thus,
a1/a2 = [G M_e / r²] / [G M_e / r²]
<em>a1/a2 = 1</em>
The circumference of the circle after t seconds = 25.12 t
Given data,
The radius of each circular wave will increase by four centimeters per second (cm/s)
In 1 second of circular wave radius = 4cm
In 1*t second of circular wave radius = 4t cm
As a result, the radius of the circular wave after t seconds is 4t cm.
We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.
As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t
= 8πt
( Taking π = 3.14 )
As a result, the circumference of the circle after t seconds = 8πt
= 3.14t
= 25.12t
Find more on circumference at : brainly.in/question/49774764
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