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Masteriza [31]
3 years ago
14

3.) If Lebron James has a vertical leap of +1.35 m. then what is his takeoff speed7 For this

Physics
2 answers:
Scilla [17]3 years ago
7 0
D, I hoped that helped you
melomori [17]3 years ago
7 0

The answer is 5.14 m/s is the answer. None of the options were correct.

Option: d

Explanation:

This is a question of kinematics. In the given question, acceleration a=-9.8 \mathrm{m} / \mathrm{s}^{2}

Vertical loop of James is s = 1.35 m  

Final velocity of James is v = 0  

We are required to find the take-off speed of James i.e., using the second equation of motion,  

v² = u² + 2as

0-u^{2}=2 \times(-9.8) \times 1.35

-\mathrm{u}^{2}=-19.6 \times 1.35

\mathrm{u}^{2}=26.46

u = 5.14 m/s (approx)  

So, the answer is none of the choices.

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A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta
My name is Ann [436]

Answer:

a).K=528.92 \frac{N}{m}

b).m=4.84kg

Explanation:

a).

The work of the spring is find by the formula:

w_s =\frac{1}{2}*k*x^2

So knowing the work can find the constant K'

3.2J =\frac{1}{2}*k*(0.11m)^2

Solve for K'

K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}

K=528.92 \frac{N}{m}

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

F=m*a

m=\frac{F}{a}=\frac{K*x}{a}

m=\frac{528.9*0.11m}{12m/s^2}

m=4.84kg

8 0
3 years ago
What are the 3 basic parts of an atom and what are their charges?
kotegsom [21]

Answer:

electrons neutrons and protons

Explanation:

electron are negative

nuetron are neutral

protons are positive

7 0
3 years ago
When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a
sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}

  = 4.59\times 10^{-19} \ J

or,

  = \frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}

  = 2.87 \ eV

(b)

As we know,

⇒ Vq=\frac{hc}{\lambda}-\Phi_0

By substituting the values, we get

⇒ 1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0

⇒                       \Phi_0=2.3\times 10^{-19} \ J

or,

⇒                            =\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}

⇒                            =1.4375 \ eV

5 0
3 years ago
For the airfoil and conditions in Problem 2.2, calculate the lift-to-drag ratio. Comment on its magnitude.
raketka [301]

Answer:

L/D= 112

Explanation:

Aerodynamics can be defined as the branch of dynamics which deals with the motion of air, their properties and the interaction between the air and solid bodies.

Aerodynamics law explains how an airplane is able to fly. There are four forces of flight, and they are; lift, weight, thrust and drag. The amount of lift generated by a wing divided by the aerodynamic drag is known as the lift to drag ratio.

Lift increases proportionally to the square of the speed.

The solutions to the question is the file attached to this explanation.

Lift,L= qC(l). S---------------------------(1).

and,

Drag,D = qC(d).S ----------------------(2).

Hence, Lift to drag ratio,L/D= C(l)/C(d).

Therefore, we have to compute various angle of attack.(check attached file)...

Then, (L/D) will then be equal to 112.

8 0
3 years ago
What is average speed?what is the formula for average speed?what does it mean?
Rama09 [41]
Average speed = total distance traveled/total time taken
it is the total distance traveled in a total time the total distance is attained
4 0
3 years ago
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