The diagram below shows the movement of Earth plates. The <span>feature that is most likely formed as a result of the movement of Earth plates shown in the diagram is a fault. The answer is letter A.</span>
Answer:
Part A: Hexacyanoferrate (III)
Part B: DiammintetraaquoCupperate (II)
Part C: Dichlorobis(ethylenediamine) Chromate (II)
Part D: Triaquocarbonylnickel (II) Sulphate
Part E: Potassium Dicarbonatedifluoroplatinate (II)
Explanation:
For naming the complex ions there is a specific rule
Nomenclature of the complex ions are as follow
- write a correct formulae
- Indicate the oxidation number of metal in the complex
- The oxidation number should write in the roman numeral in perenthasis after metal name
- Ligand named before the metal ion
- Ligan can be named in following order
* 1st negative, 2nd neutral, 3rd positive
* If there are more than 2 same charged ligand the write in
alphabetical order.
- Write prefix i.e di, tri, tetra for multiple monodentate ligands
- Anions name end at ido the replace the final name.
- Neutral ligands named as their usual name, but there are some exceptions such as
NH3 named as ammine
H2O names aqua or aquo
CO named ascarbonyl
NO named as nitrosyl
- If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
- The name of full complex will end with cation or anion with separate word.
Keeping the rules in mind the complexes named as following.
_________________________
Part A:
[Fe(CN)₆]³⁻
Name of the Complex : Hexacyanoferrate (III)
___________________
Part B:
[Cu(NH₃)₂(H₂O)₄]²⁺
Name of the Complex : DiammintetraaquoCupperate (II)
_______________________
Part C
CrCl₂(en)₂
Name of the Complex : Dichlorobis(ethylenediamine) Chromate (II)
________________________
Part C
[Ni(H₂O)₃(CO)]SO₄
Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate
______________________
Part E
K₄[Pt(CO₃)₂F₂]
Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)
Answer: 5.66 dm3
Explanation:
Given that:
Volume of neon gas = ?
Temperature T = 35°C
Convert Celsius to Kelvin
(35°C + 273 = 308K)
Pressure P = 0.37 atm
Number of moles N = 0.83 moles
Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
0.37atm x V = 0.83 moles x 0.0082 atm dm3 K-1 mol-1 x 308K
0.37 atm x V = 2.096 atm dm3
V = (2.096 atm dm3 / 0.37atm)
V = 5.66 dm3
Thus, the volume of the neon gas is 5.66 dm3
Answer:
A) 54.04%
B) 13-karat
Explanation:
A) From the problem we have
<em>1)</em> Mg + Ms = 9.40 g
<em>2)</em> Vg + Vs = 0.675 cm³
Where M stands for mass, V stands for volume, and g and s stand for gold and silver respectively.
We can rewrite the first equation using the density values:
<em>3)</em> Vg * 19.3 g/cm³ + Vs * 10.5 g/cm³ = 9.40
So now we have<em> a system of two equations</em> (2 and 3) <em>with two unknowns</em>:
We <u>express Vg in terms of Vs</u>:
We <u>replace the value of Vg in equation 3</u>:
- Vg * 19.3 + Vs * 10.5 = 9.40
- (0.675-Vs) * 19.3 + Vs * 10.5 = 9.40
- 13.0275 - 19.3Vs + 10.5Vs = 9.40
Now we <u>calculate Vg</u>:
- Vg + 0.412 cm³ = 0.675 cm³
We <u>calculate Mg from Vg</u>:
- 0.263 cm³ * 19.3 g/cm³ = 5.08 g
We calculate the mass percentage of gold:
- 5.08 / 9.40 * 100% = 54.04%
B)
We multiply 24 by the percentage fraction:
- 24 * 54.04/100 = 12.97-karat ≅ 13-karat
