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solong [7]
2 years ago
15

The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?

Chemistry
1 answer:
Inessa05 [86]2 years ago
6 0

Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

                          PbBr₂ ----------> Pb⁺² + Br⁻

                                                     S      2S

Ksp = [Pb⁺²] [ Br⁻]

Ksp = (S) (2S)²

Ksp = 4S³

6.60 × 10⁻⁶ = 4S³

S = 0.0118M

Hence, the Molar solubility S is 0.0118M.

Learn more about Molar solubility here, brainly.com/question/16243859

#SPJ4

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Explanation:

“The isomers butane and methyl propane have the same molecular formula and different properties”, this is because structural isomers usually have different properties to their parent.

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3 years ago
Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?
Irina18 [472]

Answer:

p_2=1.17atm

Explanation:

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In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm

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7 0
3 years ago
compound 1 contains 15.0g of hydrogen and 120.0g oxygen. What is the percent compound of each element?
allsm [11]

Note down the formula below

\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}

Mass of the compound

\\ \sf\longmapsto 15+120=135g

Mass % of Hydrogen:-

\\ \sf\longmapsto \dfrac{15}{135}\times 100

\\ \sf\longmapsto \dfrac{1}{9}\times 100

\\ \sf\longmapsto 11.1\%

Mass % of Oxygen:-

\\ \sf\longmapsto \dfrac{120}{135}\times 100

\\ \sf\longmapsto \dfrac{8}{9}\times 100

\\ \sf\longmapsto 88.9\%

8 0
3 years ago
In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z
storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2: </u>Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0
3 years ago
How many grams of molecular chlorine will be required to completely react with 0.0223 moles of sodium iodide according to the fo
Alecsey [184]

Answer: a

aa

Explanation: a

aaa

8 0
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