For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as
A’ = 0.16138
<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>
Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
Generally, the equation for the Beer’s law is mathematically given as
A = ε*c*l
0.8069 = ε*c*(5.00 )
ε*c = 0.16138 cm-1
then for when ε*c is constant
l’ = 1.00
A’ = (0.16138 cm-1)*(1.00 cm)
A’ = 0.16138
In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is
A’ = 0.16138
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brainly.com/question/3004869
Answer: 34.4 g
Explanation:
As 
is in excess, 
is the limiting reagent and thus it will limit the formation of products.
According to stoichiometry:
2 moles of hydrogen produce = 1 mole of 
2.5 moles of hydrogen produce = 
of
Mass of 
But as % yield is 86%, mass of produded is 
Thus 34.4 g of is produced.
Answer: Primary consumers make up the second trophic level. They are also called herbivores. They eat primary producers—plants or algae—and nothing else. For example, a grasshopper living in the Everglades is a primary consumer
The average atomic mass of N2 is 14.0067. The atomic masses of the 2 stable isotopes of nitrogen, N-14 and N-15, are14.003074002 and 15.00010897 amu, respectively. Calculate the percent abundance of each nitrogen isotope. Ex.: The average atomic weight of copper is 63.5amu .
hope this helps!!!
The grams of sodium chloride that will be made is 292.5 g
<u><em>calculation</em></u>
2Na +Cl₂ → 2NaCl
step 1: calculate the moles of Na
moles = mass/molar mass
From periodic table the molar mass of Na = 23 g/mol
moles = 115 g/23 g /mol = 5 moles
Step 2 : use the mole ratio to determine the moles of NaCl
Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also= 5 moles
Step 3: find the mass of NaCl
mass= moles x molar mass
The molar mass of NaCl = 23 + 35 .5 =58.5 g/mol
mass= 5 moles x 58.5 g/mol =292.5 g
