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AleksandrR [38]
4 years ago
12

Given the quadratic equation ax²-5b+4a=0, where a and b are constants has two real an equal roots,find a:b​

Mathematics
1 answer:
sergiy2304 [10]4 years ago
5 0

Answer:

Therefore either a:b = 5:4 or a:b=-5:4

Step-by-step explanation:

ax²-5bx+4a=0

Since the quadratic equation has two real root.

Then b²-4ac>0

Here a= a , b= -5b and c=4a

∴(-5b)²-4.a.4a=0

⇔25b²=16a²

⇔5b=±4a

\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}

Therefore either a:b = 5:4 or a:b=-5:4

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