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AleksandrR [38]
3 years ago
12

Given the quadratic equation ax²-5b+4a=0, where a and b are constants has two real an equal roots,find a:b​

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

Therefore either a:b = 5:4 or a:b=-5:4

Step-by-step explanation:

ax²-5bx+4a=0

Since the quadratic equation has two real root.

Then b²-4ac>0

Here a= a , b= -5b and c=4a

∴(-5b)²-4.a.4a=0

⇔25b²=16a²

⇔5b=±4a

\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}

Therefore either a:b = 5:4 or a:b=-5:4

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Layla has $2 worth of dimes and quarters. She has 6 more dimes than quarters. By
fredd [130]

Answer:

Layla has 4 quarters and 10 dimes

Step-by-step explanation:

A quarter each is 25 cents. And a dime each is 10 cents. counts from 10 10 times and then add 25 4 times and you get 200 which is 2 dollars. Example: 10 20 30 40 50 60 70 80 90 100 with 10 dimes alone that's a dollar 4 quarters equal another dollar so both of those equal 2 dollars. Layla had 4 dimes and 4 quarters when she added 6 more dimes it all equaled 2 dollars. Hopefully this makes sense.

3 0
2 years ago
The Kilgore family traveled 35,000 meters to get to the nearest amusement park . How many kilometers did they have to travel ?
Diano4ka-milaya [45]

Answer: the answer would be 35 kilometers

Step-by-step explanation:35000 divided by 1000 equals 35

4 0
3 years ago
Read 2 more answers
Cesars net worth is 8,250.63 his liabilities are 3,222.35 what is cesars assets
SashulF [63]

Given parameters:

Net worth of Cesar = 8250.63

Liabilities = 3222.35

Unknown:

Cesar's asset = ?

Solution:

A person's net worth is their Assets minus liability;

             Net worth  = Assets - Liabilities

  Assets  = Net worth + Liabilities

              For Cesar;

 Assets  = 8250.63 + 3222.35 = 11472.98

Cesar's assets is  11472.98

8 0
3 years ago
Consider the following hypothesis test H0 p 20 Ha p 20 A sample of 400 provided a sample proportion p 175 a Compute the value of
Bogdan [553]

Answer:

a) -1.25

b) 0.2112

c) -1.96

Step-by-step explanation:

Data provided in the question:

Sample size, n = 400

H0 : p = 20

\bar{p} = 175

Now,

a) The test statistic is  given as:

Z = \frac{(\bar{p}-p)}{\sqrt{\frac{p(1-p)}{n}}}

on substituting the respective values, we get

Z = \frac{(0.175-0.2)}{\sqrt{\frac{0.2\times0.8}{400}}}

= -1.25

b) The p-value = 2 × P(Z <-1.25)

Now from the standard normal table

P(Z <-1.25) = 10.56% = 0.1056

Thus,

p-value = 2 × 1056 = 0.2112

c) for a = 0.05,

the critical value is Z_{\frac{a}{2}}=Z_{\frac{0.05}{2}} i.e Z_{0.025}

Now from standard normal table

Z_{0.025} = -1.96

3 0
3 years ago
A bag contains 17 cards numbered 1 through 17. A card is randomly chosen from the bag. What is the probability that the card has
enyata [817]

Answer: 5/17

Step-by-step explanation:

Step 1: write all numbers from 1 to 17:

(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17)

Step 2: list all numbers in the space which are multiples of 3:

(3,6,9,12,15)

Probability that the card has a multiple of three of it is derived by dividing number of possible outcomes by number of total outcomes

No of possible outcomes=5

No of total outcomes =17

Pr (card drawn has multiple of 3) = 5/17

I hope this helps, please mark as brainliest answer.

6 0
3 years ago
Read 2 more answers
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