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son4ous [18]
3 years ago
11

AB is perpendicular to CD. If the slope of AB is 2/5, what is the slope of CD?​

Mathematics
1 answer:
alekssr [168]3 years ago
4 0

Given a slope m, the slope m' of a line perpendicular to m is the opposite of the inverse of m

In other words:

mm' = -1 \iff m' = -\dfrac{1}{m}

So, the slope of CD is -5/2.

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Answer:

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Step-by-step explanation:

first find angle E.

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E = 180 - 90 - 20 = 70 degrees

now we use the law of sines.

ED/sin(20) = DC/sin(70) = EC/sin(D)

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sin(D) = sin(90) = 1

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How to find average value of a function over a given interval?
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3 0
3 years ago
What is the shaded portion of the circle
blagie [28]

Answer:

(5\pi-11.6)\ ft^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

A=\pi r^{2}

we have

r=5\ ft

substitute

A=\pi (5)^{2}

A=25\pi\ ft^{2}

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

so

by proportion find out the area of a sector by a central angle of 72 degrees

\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}

step 3

Find the area of triangle

The area of the triangle is equal to

A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

(5\pi-11.6)\ ft^{2}

8 0
3 years ago
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