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gladu [14]
3 years ago
9

How much heat does it take to melt a 0.234 kg ice cube at its melting point?

Physics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

77922J

Explanation:

Thermal Energy used

= Energy used to change state from solid to liquid

= <em>m</em><em>l</em><em>f</em><em> </em> [Formula of latent heat of fusion]

= <em>(</em><em>0</em><em>.</em><em>2</em><em>3</em><em>4</em><em>)</em><em>(</em><em>3</em><em>.</em><em>3</em><em>3</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em>^</em><em>5</em><em>)</em>

= <u>7</u><u>7</u><u>9</u><u>2</u><u>2</u><u> </u><u>J</u>

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An FM radio station broadcasts at 9.23 × 107 Hz. Given that the radio waves travel at 3.00 × 108 m/s, what is the wavelength of
STALIN [3.7K]

Answer:

3.2m

Explanation:

Given parameters:

Frequency of the FM radio = 9.23 x 10⁷Hz

Velocity of the waves = 3  x 10⁸m/s

Unknown:

Wavelength of the wave = ?

Solution:

To solve for the wavelength of the wave, we need the velocity equation;

       Velocity = frequency x wavelength.

Radio waves are all electromagnetic radiations produced by both electrical and magnetic fields perpendicularly oriented to one another.

 Since the unknown is wavelength, we solve for it:

       

    3  x 10⁸  = 9.23 x 10⁷ x wavelength

          wavelength = \frac{ 3 x 10^{8} }{9.23 x  10^{7} }

        wavelength = 3.2m

7 0
4 years ago
a motor pulls up a block suspended on a string, so that the tension in the string is equal to the qeight force on the block. the
Sindrei [870]

Answer:

Explanation:

Let T be the tension in the string and mg is the weight of the block.

T = mg

By using Newton's second law

T - mg = ma

mg - mg = ma

a = 0

Thus, the acceleration is zero.

8 0
3 years ago
Two books are located 1 m above the surface of the Earth. The first has a mass of 2 kg; the second has a mass of 1 kg. Which sta
stepladder [879]
B, the acceleration due to gravity is 9.8m/s/s regardless of mass

3 0
3 years ago
if the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is fa
Nookie1986 [14]

1. What is the force of the marble?

For an object near the surface of the earth, the gravitational force acting upon the object is given by:

F = mg

F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

Given values:

m = 0.025kg, g = 9.8m/s²

Plug in the given values and solve for F:

F = 0.025×9.8

F = 0.25N

2. What is the marble's potential energy at the start of its fall?

The gravitational potential energy of an object near the earth's surface is given by:

PE = mgh

PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

new given values:

h = 0.08m

Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:

PE = F×h

PE = 0.25×0.08

PE = 0.02J

4 0
3 years ago
Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon
posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

4 0
4 years ago
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