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eduard
3 years ago
5

Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the

second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge?
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

in first case the torque is maximum.

Explanation:

Torque is defined as the product of force and the perpendicular distance.

τ = F x d x Sinθ

In case A: the angle between force vector and the distance vector is 90 so torque is

τ = F x d

In case B: the angle between force vector and the distance is 30°.

τ = F x d x Sin30

τ = 0.5 Fd

So the torque is maximum in first case.

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