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Aleksandr-060686 [28]
4 years ago
12

Coach Hogue is riding his motorcycle in a circle on wet pavement. Suddenly the bike slides out from under him. What failed to pr

ovide enough Centripetal Force to maintain coach Hogue's circular motion Group of answer choices Inertia Force Force of Friction Spring Force Force of Gravity
Physics
1 answer:
Arisa [49]4 years ago
5 0

Answer:

The correct option is;

Force of Friction

Explanation:

As coach Hogue rode his motorcycle round in circle on the wet pavement, the motorcycle and the coach system tends to move in a straight path but due to intervention by the coach they maintain the circular path

The motion equation is

v = ωr and we have the centripetal acceleration given by

α = ω²r and therefore centripetal  force is then

m×α = m × ω²r = m × v²/r

The force required to keep the coach and the motorcycle system in their circular path can be obtained by the impressed force of friction acting towards the center of the circular motion.

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I don't think so it would be some where between 9 and 10
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4 years ago
What is the kinetic energy of a 3.8kg ball that is rolling at 2.2 m/s
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Kinetic energy =  0.5 x m x v²
Kinetic energy = 0.5 x 3.8 x 2.2²
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3 years ago
According to this graph, which statement describes how the amount of iron changes over time in the reaction
melamori03 [73]
The graph shows the production of Fe.
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3 years ago
A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b
Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, \alpha=10\ rad/s^2

Time taken, t = 3 seconds

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\alpha=\dfrac{\omega_f-\omega_i}{t}

\omega_i=0\ (rest)

\omega_f=\alpha t

\omega_f=10\ rad/s^2\times 3\ s

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8 0
3 years ago
Isaac throws an apple straight up (in the positive direction) from 1.0m above the ground, reaching a maximum height of 35 meters
Assoli18 [71]
Consider that when heigt is 35 meters, the velocity is zero. The you can use the formula for free fall with initial velocity zero

Vf = √(2gh) = √(2*9.8m/s^2 * 35m) = √686m^2/s^2 = 26.2 m/s

Assumption: 35 m is the maximum height from the ground, else, if the maximum heigth from the ground is 35 m + 1 m = 36 m, the numbers are:

Vf = √(2*9.8m/s^2*36m) = 26.6 m/s
5 0
3 years ago
Read 2 more answers
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