Answer: 9 days
Explanation:
Let the rate of Leaf growth <em>r</em> be defined as,
= 
where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.
- Express the proportional relationship in equation.
Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.
r = kA, where k is the rate constant.
therefore, k = 
when A = 2
, A1 = 3
so k = 
=
÷ 2
= 0.33 ÷ 2
k = 0.167
- After calculating the rate constant k, we then find the time t when A1 is 5

- we have r = k × A1 =

so, 0.167 × 2 = 
0.33 =
.
t = 3/0.33
Therefore, t = 9 days.
Explanation:
First, we will calculate the electric potential energy of two charges at a distance R as follows.
R = 2r
= 
= 0.2 m
where, R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.
U = 
= 
= 0.081 J
As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.
Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is,
.
Hence, K.E = 
= 
= 0.0405 J
Now, we will calculate the speed of balls as follows.
V = 
= 
= 0.142 m/s
Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.
Explanation:
What characteristics must the movement of a person have so that the value of the displacement is equal to the distance traveled?
Displacement is equal to the shortest path covered by an object. It is given by the difference of final position and the initial position.
Distance is equal to the total path covered by an object during the journey.
When an object moves in a straight line path, in this case, the displacement is equal to the distance traveled.
They are unbalanced forces ..... Hope this helps :3
Answer:
0.426 L
Explanation:
Boyles law is expressed as p1v1=p2v2 where
P1 is first pressure, v1 is first volume
P2 is second pressure, v2 is second volume.
Given information
P1=96 kPa, v1=0.45 l
P2=101.3 kpa
Unknown is v2
Making v2 the subject from Boyle's law

Substituting the given values then

Therefore, the volume is approximately 0.426 L