The kinetic energy of the cart is 24 J.
<u>Explanation:</u>
The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.
The kinetic energy is the given by,
K.E = 1/2 mv^2
Given the mass m = 3 kg, v = 4 m / s.
K.E = 1/2 
3 (4)^2
K.E = 24 J.
Answer:
The energy dissipated as the puck slides over the rough patch is 1.355 J
Explanation:
Given;
mass of the hockey puck, m = 0.159 kg
initial speed of the puck, u = 4.75 m/s
final speed of the puck, v = 2.35 m/s
The energy dissipated as the puck slides over the rough patch is given by;
ΔE = ¹/₂m(v² - u²)
ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)
ΔE = -1.355 J
the lost energy is 1.355 J
Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J
<span>The density of fissionable uranium is not high enough. Basically more neutrons are absorbed than are produced so any chain reaction dies. hope this helps</span>
Answer:
a) laser 1 has the maximum closest to the central maximum
b) y₂ –y₁ = L 1.66 10⁻²
Explanation:
a), B1, B2) The expression that describes the constructive interference for a double slit is
d sin θ = m λ
The pattern is observed on a screen
tan θ = y / L
Since the angles are very small
tan θ = sin θ / cos θ = sin θ = y/L
d y / L = m λ
In this case the laser has a wavelength
λ
₁ = d/20
We substitute
d y / L = m d / 20
m = 1
y₁ = L / 20
For the laser 2 λ
₂= d / 15
y₂ = L / 15
When examining the two expressions, laser 1 has the maximum closest to the central maximum
b) the difference between the two patterns is
y₂- y₁ = L (1/15 - 1/20)
y₂ –y₁ = L 1.66 10⁻²
C) laser 1 second maximum
y₁ ’= 2 L / 20
y₁ ’= L 0.1
Laser 2 third minimum
To have a minimum, the equation must be satisfied
d sin θ = (m + ½) λ
d y / L = (m + ½) λ
d y / L = (m + ½) d / 15
y = L (m +1/2) / 15
m = 3
y₂’= L (3 + ½) / 15
y₂’= L 0.2333
The difference is
y₁ ’- y₂’ = L (0.1 - 0.2333)
y₁ ’–y₂’ = L (-0.133)
Answer:
Height will be equal to 0.4489 m
Explanation:
We have given mass of the toy m = 0.50 kg
Initial kinetic energy K = 2.2 J
We have to fond the height of the hill over which car roast
When car will roast the hill its kinetic energy will be converted into potential energy and at maximum height all kinetic energy will be converted into potential energy
So at maximum height 
Acceleration due to gravity 
So 0.50×9.8×h = 2.2
h = 0.4489 m
