Question

Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, what is the magnitude of the force of attraction (in newtons) between the objects

Answer 1

Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

What is Newton's law of gravitation?

• Gravitation is the force of attraction between any two bodies.
• Every body in the universe attracts every other body with a force.
• This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.
• Mathematically we can expressed it as,

                        $F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2$

How to solve the problem?

• Here, we have given with the data's,

                      $M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m$

• Thus, the force of attraction between these two bodies will be,

               $F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN$

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

Learn more about the Newton's law of gravitation here:

brainly.com/question/28045318

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