All categories

3 years ago

H is a chemical_and H2 is a chemical_?

Physics

1 answer:

Korvikt [17]3 years ago

4 0

Answer:

H is a chemical symbol

and H2 is a chemical formula because hydrogen cannot be written H only

Explanation:

H = Atomic Hydrogen

Atomic Hydrogen cropped-Atomic hydrogen is number 1 on the Periodic Table of Elements. It consists of one proton and one unpaired electron which means that it is a free radical.

However an atom of hydrogen rarely exists on its own because its unpaired electron eagerly seeks to join up with another electron.

The molecular form of hydrogen is more common.

H2 = Molecular Hydrogen

H2 is a gas which forms when two hydrogen atoms bond together and become a hydrogen molecule. H2 is also called molecular hydrogen.It consists of two protons and two electrons. Consequently it is the most common form of Hydrogen because it is stable with a neutral charge. H2 is not a free radical. It is the antioxidant in ‘hydrogen-rich’ water.

H2 is the smallest molecule in the universe. That means it can go where nothing else can …including into your mitochondria which are the powerhouses of your cells. Hydrogen gas cannot be kept in plastic because it will pass right through the walls of the container.

You might be interested in

Air enters a nozzle steadily at 2.21 kg/m3 and 20 m/s and leaves at 0.762 kg/m3 and 150 m/s. If the inlet area of the nozzle is

saveliy_v [14]

Answer:

a) The mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle is 23.6 cm².

Explanation:

a) The mass flow rate through the nozzle can be calculated with the following equation:

$\dot{m_{i}} = \rho_{i} v_{i}A_{i}$

Where:

$v_{i}$ : is the initial velocity = 20 m/s

$A_{i}$ : is the inlet area of the nozzle = 60 cm²

$\rho_{i}$ : is the density of entrance = 2.21 kg/m³

$\dot{m} = \rho_{i} v_{i}A_{i} = 2.21 \frac{kg}{m^{3}}*20 \frac{m}{s}*60 cm^{2}*\frac{1 m^{2}}{(100 cm)^{2}} = 0.27 kg/s$

Hence, the mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle can be found with the Continuity equation:

$\rho_{i} v_{i}A_{i} = \rho_{f} v_{f}A_{f}$

$0.27 kg/s = 0.762 kg/m^{3}*150 m/s*A_{f}$

$A_{f} = \frac{0.27 kg/s}{0.762 kg/m^{3}*150 m/s} = 0.00236 m^{2}*\frac{(100 cm)^{2}}{1 m^{2}} = 23.6 cm^{2}$

Therefore, the exit area of the nozzle is 23.6 cm².

I hope it helps you!

5 0

3 years ago

Read 2 more answers

5. Three children are at work. One is pushing a chair, another is pushing the sofa and the third one is pushing an empty trolley

katen-ka-za [31]

Answer:

sofa

Explanation:

because the sofa is heavy and the amount of friction is high due to the amount of opposite friction is pushing it back

4 0

3 years ago

How are musical instruments grouped?

rosijanka [135]

A and B are equivalent. That's one way instruments are often grouped. (the "sopranos", the "altos", the "bass")

C is another way instruments are often grouped; (the "woods", the "brass")

D is another way instruments are often grouped; (the "strings", the "percussions")

6 0

3 years ago

Read 2 more answers

Give three examples from your life of magnetic force.

Margaret [11]

Headphones, refrigerator magnets, and compasses

Hope that was helpful.

4 0

3 years ago

Read 2 more answers

How far can a sound wave travel in 90 seconds when the ambient air temperature is 10 C?

Ksju [112]

Answer:

s = 30330.7 m = 30.33 km

Explanation:

First we need to calculate the speed of sound at the given temperature. For this purpose we use the following formula:

v = v₀√[T/273 k]

where,

v = speed of sound at given temperature = ?

v₀ = speed of sound at 0°C = 331 m/s

T = Given Temperature = 10°C + 273 = 283 k

Therefore,

v = (331 m/s)√[283 k/273 k]

v = 337 m/s

Now, we use the following formula to calculate the distance traveled by sound:

s = vt

where,

s = distance traveled = ?

t = time taken = 90 s

Therefore,

s = (337 m/s)(90 s)

6 0

3 years ago

H is a chemical_______and H2 is a chemical_______?

H is a chemical_and H2 is a chemical_?