The net force on the car for either case will be zero, since the car is moving at a constant velocity.
<h3>Net force on the car</h3>
The net force on the car is the sum of all the forces acting on the car.
∑F = ma
<h3>When the car is on a level road</h3>
When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.
F - Ff = 0
The net force will be zero, since the car is moving at a constant velocity.
<h3>When the car is on uphill</h3>
The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.
F - Wsinθ - μFₙcosθ = 0
The net force will be zero, since the car is moving at a constant velocity.
Learn more about net force at constant velocity here: brainly.com/question/14392124
Answer:
approximately 30 degrees
Explanation:
If it takes the cannonball 2 seconds to reach the maximum height, we can use the analysis of the vertical component of the velocity and the fact that the acceleration of gravity is the one acting opposite to this initial vertical component 
of the velocity. We know as well that at the top of the trajectory, the vertical component of the velocity is zero, and then the movement starts going down in it trajectory. So, the final velocity for the first part of the ascending movement is zero, giving us the following equation for the velocity under an accelerated movement (with acceleration of gravity "g" acting):
By knowing the vertical component of the initial velocity (19.6 m/s), and the actual magnitude of the total initial velocity (40 m/s), we can calculate what angle was the initial velocity vector forming above the horizontal. We use for such the fact that the sine of the angle relates the opposite side of a right angle triangle with the hypotenuse, and solve for the angle using the arcsin function:
which tells us that the closer answer shown is 
The acceleration due to gravity near the surface of the planet is 27.38 m/s².
<h3>
Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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