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Vesna [10]
3 years ago
12

H is a chemical_______and H2 is a chemical_______?

Physics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

H is a chemical symbol

and H2 is a chemical formula because hydrogen cannot be written H only

Explanation:

H = Atomic Hydrogen

Atomic Hydrogen cropped-Atomic hydrogen is number 1 on the Periodic Table of Elements. It consists of one proton and one unpaired electron which means that it is a free radical.

However an atom of hydrogen rarely exists on its own because its unpaired electron eagerly seeks to join up with another electron.

The molecular form of hydrogen is more common.

H2 = Molecular Hydrogen

H2 is a gas which forms when two hydrogen atoms bond together and become a hydrogen molecule. H2 is also called molecular hydrogen.It consists of two protons and two electrons. Consequently it is the most common form of Hydrogen because it is stable with a neutral charge. H2 is not a free radical. It is the antioxidant in ‘hydrogen-rich’ water.

H2 is the smallest molecule in the universe. That means it can go where nothing else can …including into your mitochondria which are the powerhouses of your cells. Hydrogen gas cannot be kept in plastic because it will pass right through the walls of the container.

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Which of the following is NOT a property of long-period comets that suggests that they originate from the Oort cloud?
Lesechka [4]

Answer:

b. They orbit around the Sun in a counterclockwise direction, when viewed from above the ecliptic plane.

Explanation:

All the objects of the solar system revolve around the Sun in a counterclockwise direction. The comet coming from the Oort's cloud will also follow the same kind of orbit. That is why it can't be a property to distinguish an Oort's cloud comet.

All other properties are correct to identify an Oort's cloud comet as the Oort's cloud is a considered a spherical cloud just outside the Solar system.

7 0
3 years ago
Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?
bogdanovich [222]

Answer:

6 m/sec

Explanation:

12/2=6

7 0
3 years ago
A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block
mel-nik [20]

Answer:

v₁ = 0.375 m / s ,   x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

       p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

      p_{f} = (m + M) v₁

how the forces are internal

       p₀ =p_{f}

       m v₀ = (m + M) v₁

       v₁ = m /m+M    v₀

let's calculate

       v₁ = 0.4 /(0.4 + 2.8)  3

       v₁ = 0.375 m / s

 

Let's apply Newton's second law to the Block, to find the friction force

Y axis

       N - W = 0

       N = W

       N = m g

where m is the mass of the block

the friction force has the formula

      fr = μ N

      fr = μ m g

We apply Newton's second law to slab    

X axis

       fr = M a

where M is the mass of the slab

       μ m g = M a

       a = μ g m / M

let's calculate

       a = 0.15  9.8  0.4 / 2.8

       a = 0.21 m / s²

With kinematics we can find the position

       v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

       v² = 2 a x

       x = v2 / 2a

let's calculate

        x = 0.375²/2 0.21

        x = 0.335 m

4 0
3 years ago
The gravitational attraction between two masses of 3kg that are separated by a distance of 1cm is
Luba_88 [7]

Answer:

6.003×10¯⁶ N

Explanation:

We'll begin by converting 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Finally, we shall determine the gravitational attraction. This can be obtained as follow:

Mass 1 (M₁) = 3 Kg

Mass 2 (M₂) = 3 Kg

Distance apart (r) = 0.01 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 3 × / 0.01²

F = 6.003×10¯¹⁰ / 1×10¯⁴

F = 6.003×10¯⁶ N

Thus the gravitational attraction is 6.003×10¯⁶ N

6 0
3 years ago
The 300 m diameter Arecibo radio telescope is observing the Andromeda galaxy at a wavelength of 29 cm. show answer No Attempt 50
jekas [21]

Answer:

The angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad.

Explanation:

The resulting image in a telescope obtained from an object is a diffraction pattern.

That diffraction pattern is obtained because the light encounters different obstacles on its path inside the telescope (interact with the walls and edges of the instrument).

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction patterns maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in an analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}   (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 29cm \cdot \frac{1m}{100cm} ⇒ 0.29m

Finally, equation 1 can be used.

\theta = 1.22(\frac{0.29m}{300m})

\theta = 1.179x10^{-3}rad              

Hence, the angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad    

3 0
3 years ago
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