Answer:
Earth's water is always in movement, and the natural water cycle, also known as the hydrologic cycle, describes the continuous movement of water on, above, and below the surface of the Earth. Water is always changing states between liquid, vapor, and ice, with these processes happening in the blink of an eye and over millions of years.
Hope this helped!! :))
Explanation:
Here it is an application of Newton's III law
as we know by Newton's III law that every action has equal and opposite reaction
So here as we know that two boys jumps off the boat with different forces
from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude
So boat must have an opposite force on front end with magnitude 45 N
Now similar way we can say
from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude
So boat must have an opposite force on front end with magnitude 60 N
So here net force due to both jump on the boat is given by



so boat will have net force F = 15 N in forward direction due to both jumps
The image will form in the vicinity of F. Its nature will be small and inverted
Answer:
2.63 cm
Explanation:
Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension
Making c the subject of the formula then

Since F is gm but taking the given mass to be F

By substitution now considering F to be 3.3 kg

Answer:
The magnitude of the electrostatic force is 120.85 N
Explanation:
We can use Coulomb's law to find the electrostatic force between the down quarks.
In scalar form, Coulomb's law states that for charges
and
separated by a distance d, the magnitude of the electrostatic force F between them is:

where
is Coulomb's constant.
Taking the values:


and knowing the value of the Coulomb's constant:

Taking all this in consideration:

