I'm assuming your question refers to the train travels 81 km in 2 hours, as in that's the total distance covered versus the speed for those 2 hours, whereas the 90 km in 2 hours the second time around is the total distance not speed I would assume.
Now... if it was going 81 km for the first 2 hours and 90 km for the second 2 hours then the average speed would be the mean of these numbers, with that being 85.5 km. Though, I doubt that's your question.
With that said, 81 km covered by 2 hours and 90 km covered by 2 more hours. To acquire the km an hour average, we'll have to divide the distance by how many hours it traveled:
81 / 2 = 40.5
90 / 2 = 45
Meaning the train was going 40.5 km an hour for the first 2 hours and 45 km an hour for the second 2 hours. Now, to find the mean:
40.5 + 45 = 85.5 / 2 = 42.75
In-case you were wondering, the mean is the sum of all the numbers in a set, divided by the total amount of numbers in that set, take for instance:
3, 5, 9, 2, 1, 5. -> There are 6 numbers in this set.
3 + 5 + 9 + 2 + 1 + 5 = 25 -> 25 is the sum of these numbers.
25 / 6 = 4.2 (estimated) -> 4.2 is roughly the mean or average between the original set.
Anyhow, with that aside the average speed between this I would believe would be 42.75 km an hour. I hope that helps, have a great rest of your day! ^ ^
| | Ghostgate (Alter) | |
Answer:
The answer is C. it will evaporate.
Explanation:
500 N is the answer, you just tell that the moon is attracted towards the person because of the Earth's huge mass.
Answer:
anions
Explanation:
The other are families of the periodic table.
An anion is a negatively charged ion.
To determine the gas which has the higher initial temperature, we need an equation that would relate energy and temperature. From thermodynamics, we use the expression Energy = nCvT where n is the number of moles, Cv is the heat capacity at constant volume and T is the temperature. By evaluating the temperature of both gases we determine the which would have higher temperature.
4800 = 2.3CvT
T = 2086.96/Cv
8500 = 2.9CvT
T = 2931.03/Cv
Assuming that both gases are the same. Therefore, the value of Cv for both would be equal. So, we conclude that it is the second gas with 2.9 moles would have the higher initial temperature.