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GarryVolchara [31]
3 years ago
6

The clouds that occur at the highest altitude are usually

Physics
2 answers:
babunello [35]3 years ago
7 0
<span> cirrus hope this helps </span>
gogolik [260]3 years ago
5 0
The answer is A. Cirrus clouds occur at the highest altitude.
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What is the source of the radioactive nuclei present in spent fuel rods?
Debora [2.8K]
The answer is <span>nuclear fission.  T</span>he source of the radioactive nuclei present in spent fuel rods is nuclear fission.  Nuclear fission<span> is the </span>process<span> in which a large nucleus splits into two smaller nuclei with the release of energy. </span>
6 0
2 years ago
A spring of force constant 1500 Nm-l is acted
olchik [2.2K]

Answer:

1.876 J

Explanation:

First, let’s calculate the compression of the spring from the Hooke’s law:

F=kx,

here, F=75 N is the force acted on the spring, k=1500 N⁄m is the force constant of the spring, x is the compression of the spring.

Then, we get:

x=F/k=(75 N)/(1500 N/m)=0.05 m.

Finally, we can find the potential energy stored in the spring:

PE=1/2 kx^2=1/2∙1500 N/m∙(0.05 m)^2=1.875 J.

correct my answer if it's wrong ^^

7 0
3 years ago
A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is
tigry1 [53]

Answer:

6.86 meters

Explanation:

Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.

So that;

x = 9 cm = 0.09 m

In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;

PE = \frac{1}{2} Kx^{2}

    = \frac{1}{2} x 830 x (0.09)^{2}

    = 415 x 0.0081

    = 3.3615

The potential energy in the string = 3.36 Joules

Also,

PE = mgh

where: m is the mass, g is the gravitational force and h the height.

m = 50 g = 0.05 kg, g = 9.8 ms^{-2}

Thus,

PE = 0.05 x 9.8 x h

3.3615 = 0.05 x 9.8 x h

3.3615 = 0.49h

⇒ h = \frac{3.3615}{0.49}

      = 6.8602

The height of the toy rocket would be 6.86 meters.

4 0
2 years ago
A cloud is drifting across the sky at a constant velocity of 724metersperminute to the east. It is at an altitude of 9,200 meter
alisha [4.7K]

Answer:

The cloud moves 9050 meters to the east in 12.5 minutes.

Explanation:

Let suppose that mass of the cloud is negligible. meaning that effects of gravity are negligible and that altitude of the cloud remains constant. If the cloud drifts at constant velocity, travelled distance is defined by following formula:

\Delta s = v\cdot \Delta t (1)

Where:

v - Velocity, in meters per second.

\Delta t - Time, in seconds.

If we know that v = 724\,\frac{m}{min} and \Delta t = 12.5\,min, then the travelled distance after 12.5 minutes is:

\Delta s = 9050\,m

The cloud moves 9050 meters to the east in 12.5 minutes.

7 0
2 years ago
I REALLY NEED HELP ON THIS PLEASE HELP ME
Lapatulllka [165]

Answer:

I have no clue lol

Explanation:

8 0
2 years ago
Read 2 more answers
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