Answer:
So trees in temperate don't lose their leaves because the weather events aren't harsh enough.
Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.
Explanation:
Ok so first we'll define some things
Deciduous Trees= Trees that lose all of their leaves for part of the year.
Trees shed their leaves trees to try and survive harsh weather events.
Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.
Temperate rainforests = An area that doesn't experience extremely cold or extremely hot temperatures or what we would call harsh weather events.
Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.
Answer: The name of the 
is Iodine tetrabromide and it is a covalent compound.
Explanation:
Inter-halogen compounds are compounds which composed of two different halogen atoms. For example ;
etc.
The naming is done by first writing the central atom symbol's name followed by the prefix corresponding to the number of atoms of another halogen atom like: Mono for 1, di ,for 2 tri for 3, tetra for 4 , penta for 5 etc. After this name of the another halogen is written with suffix 'ide' in the end.
The name of the is Iodine tetra bromide.
In halogen compounds, the difference in electronegativities is not so large due to which they form covalent compounds by the means of sharing the electrons. Hence the Iodine tetrabromide covalent compound.
Answer:
2KClO3--------->2KCl + 3O2
C :)
I know this is right, I learned about this last year so I would really appreciate a brainliest
have a good day bud :)
Answer:
23.46 mmHg is the vapor pressure for the solution
Explanation:
To solve this problem we need to apply a colligative property, which is the lowering vapor pressure.
The formula for this is: P°- P' = P° . Xm
where P' is vapor pressure for solution and P°, vapor pressure for pure solvent.
Let's determine the Xm (mole fraction for solute)
We calculate the moles of the solute and the solvent and we sum each other:
Moles of solute: 60 g /342 g/mol = 0.175 moles of sucrose
Moles of solvent: 250 g / 18 g/mol = 13.8 moles of water
Total moles: 13.8 moles + 0.175 moles = 13.975 moles
Xm for solute: 0.175 moles / 13.975 moles = 0.0125
Let's replace data in the formula: 23.76 mmHg - P' = 23.76 mmHg . 0.0125
P' = - (23.76 mmHg . 0.0125 - 23.76 mmHg) → 23.46 mmHg
