They need 10 tutors if the academy has 120 students.
same as before, is the proportion of one, the same as the other? let's do the same here without much fuss.
![\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{~~2\frac{1}{3}~~}{\frac{3}{4}}=\cfrac{~~4\frac{2}{3}~~}{1\frac{1}{2}}\implies \cfrac{~~\frac{7}{3}~~}{\frac{3}{4}}=\cfrac{~~\frac{14}{3}~~}{\frac{3}{2}}\implies \cfrac{7}{3}\cdot \cfrac{4}{3}=\cfrac{14}{3}\cdot \cfrac{2}{3}\implies \cfrac{28}{9}=\cfrac{28}{9}~~\textit{\Large \checkmark}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B3%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Ccfrac%7B~~2%5Cfrac%7B1%7D%7B3%7D~~%7D%7B%5Cfrac%7B3%7D%7B4%7D%7D%3D%5Ccfrac%7B~~4%5Cfrac%7B2%7D%7B3%7D~~%7D%7B1%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B~~%5Cfrac%7B7%7D%7B3%7D~~%7D%7B%5Cfrac%7B3%7D%7B4%7D%7D%3D%5Ccfrac%7B~~%5Cfrac%7B14%7D%7B3%7D~~%7D%7B%5Cfrac%7B3%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B3%7D%3D%5Ccfrac%7B14%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B2%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B28%7D%7B9%7D%3D%5Ccfrac%7B28%7D%7B9%7D~~%5Ctextit%7B%5CLarge%20%5Ccheckmark%7D)
Answer: The bus traveled at an average speed of 40 km/h and she - 2385764. ... bus from her home to the bank and then walked back to her home along the same route. ... To determine the time, x, that it took Talia to walk home, she used the equation 40(0.9 – x) = 5x. 1 ... Therefore, it took Talia 0.8 hour to walk home or 48 minutes
Step-by-step explanation:
Answer:
17.2
Step-by-step explanation:
3x=12+y
x=12+y/3
(y is divided by y so it no longer exists)
Answer:
C
Step-by-step explanation:
the "-" sign can't be true, because that would have turned the whole graph of x² upside-down. but it is not.
so, we need a positive sign for the x term.
and the whole graph is shifted to the right. so the functional value of x of F(x) is now the same that happened "earlier" (for smaller x) with G(x). so, the argument "x" is now reduced (by 3 units, as the graph is shifted right by 3 units) in the calculation compared to the original G(x) calculation.
therefore, the ...(x-3)... expression is right.
so, positive sign and "(x-3)" is only in C.
