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shutvik [7]
3 years ago
14

How fast would a(n) 85 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 410 m/s?

Physics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

V = 3.97 m/s

Explanation:

Mass of a man, M = 85 kg

Mass of a bullet, m = 8 g = 0.008 kg

Speed of bullet, v = 410 m/s

We need to find the speed of a man in order to have the same kinetic energy as that of the bullet. Let the kinetic energy of the bullet is k. So,

k=\dfrac{1}{2}mv^2\\\\k=\dfrac{1}{2}\times 0.008\times 410^2\\\\k=672.4\ J

Since, k = K (K is the kinetic energy of the man and Let V is the speed)

K=\dfrac{1}{2}MV^2\\\\V=\sqrt{\dfrac{2K}{M}} \\\\V=\sqrt{\dfrac{2\times 672.4}{85}} \\\\V=3.97\ m/s

So, the speed of the man is 3.97 m/s.

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it will not change

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Projectile Motion: A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3
marin [14]

Answer:

The angle of launch from the horizontal direction is 20.99° .

Explanation:

Let u and θ be the initial speed and angle of projection from the horizontal axis of the object respectively.

The equations for projectile motion are :

H = ( u² sin²θ)/ 2g      ......(1)

Here H is maximum height of the projectile motion and g is acceleration due to gravity.

R = ( u² sin2θ)/g         .......(2)

Here R is the maximum horizontal displacement of the object.

Rearrange equation (1) in terms of u².

u² = (2gH)/sin²θ

Substitute this equation in equation (2).

R = (2gH sin2θ) / (sin²θ x g)

R = (2H sin2θ)/sin²θ

Using trigonometry property, sin2θ = 2 cosθ sinθ

So, above equation becomes,

R = (2H x 2 cosθ sinθ)/sin²θ

R = (4H cosθ)/sinθ

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θ = tan⁻¹(R/4H)

Substitute 111 m for R and 72.3 m for H in the above equation.

θ = tan⁻¹( 111/ 4 x 72.3 )

θ = tan⁻¹(0.38)

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3 0
3 years ago
A football player kicks a 0.94 kg football with a force of 2.4 N.
Artyom0805 [142]

2.6m/s²

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Given parameters:

Mass of football = 0.94kg

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Unknown:

The acceleration of the ball = ?

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According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

  Net force = mass x acceleration

Make acceleration the subject of the expression;

       Acceleration = \frac{net force}{mass}

Acceleration  = \frac{2.4}{0.94}  =  2.6m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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Benjamin threw a rock straight up from a cliff that was 36 ft above the water. if the height of the rock​ h, in​ feet, after t s
never [62]
For this case we have the following equation:
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6 0
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