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3 years ago

7

Choose the 200 kg refrigerator. Set the applied force to 400 N (to the right). Be sure friction is turned off.What is the net fo

rce acting on the refrigerator?

2 answers:

White raven [17]3 years ago

3 0

So, there should be two forces acting on the refrigerator: the applied force and the friction force.

The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.

We have an applied force of 400 N to the right, this means that:
<span>The magnitude of the net force is 400, directed to the right.</span>

babymother [125]3 years ago

3 0

The net force acting on the refrigerator is 400 N to the right

$\texttt{ }$

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\boxed {F = ma }$

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

$\texttt{ }$

<u>Given:</u>

mass of refrigerator = m = 200 kg

magnitude of applied force = F = 400 N

magnitude of frictional force = f = 0 N

<u>Asked:</u>

net force = ΣF = ?

<u>Solution:</u>

<em>We will use </em><em>Newton's Law of Motion</em><em> to solve this problem as follows:</em>

$\Sigma F = F - f$

$\Sigma F = 400 - 0$

$\boxed{\Sigma F = 400 \texttt{ N} }$

$\texttt{ }$

<em>We could also calculate the acceleration of the refrigerator as follows:</em>

$\Sigma F = ma$

$a = \Sigma F \div m$

$a = 400 \div 200$

$\boxed{a = 2 \texttt{ m/s}^2 }$

$\texttt{ }$

<h3>Learn more</h3>

Impacts of Gravity : brainly.com/question/5330244
Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
The Acceleration Due To Gravity : brainly.com/question/4189441
Newton's Law of Motion: brainly.com/question/10431582
Example of Newton's Law: brainly.com/question/498822

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

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As per Newton's II law we can say

Force applied is rate of change of momentum

$F = \frac{dP}{dt}$

here we have

$dP = P_f - P_i$

$dP = mv_f - mv_i$

given that

m = 0.25 kg

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F = 460 N

now by above equation

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4 years ago

An astronaut drops a marble on the surface of Mars and observes that it takes 1.02 s for the marble to fall 2.00 m. She also kno

Irina-Kira [14]

Answer:

The mass of mars is $6.61\times10^{23}\ kg$

Explanation:

Given that,

Time = 1.02 s

Height = 2.00 m

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We need to calculate the acceleration due to gravity on mars

Using equation of motion

$h = ut+\dfrac{1}{2}gt^2$

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Where, u = initial velocity

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Put the value into the formula

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We need to calculate the mass of mars

Using formula of gravity

$g=\dfrac{Gm}{r^2}$

Put the value into the formula

$3.84=\dfrac{6.67\times10^{-11}\times m}{(3.39\times10^{6})^2}$

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3 years ago

Explain the term the refractive index of glass is 1.5

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Answer:

Refractive index of a glass is 1.5 means that the speed of light travels 1.5 times SLOWER in that glass than in a vacuum.

Explanation:

Refractive index is defined as a ratio between the speed of light in a vacuum and the speed of light in a medium. Since the refractive index is a ratio between two speeds it is a dimensionless number. For the glass, having a refractive index of 1.5, means that the speed of light travels 1.5 times SLOWER in that glass than in a vacuum.

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3 years ago

Suppose that the loudspeaker in the problem had a mass of 500 kg and the ropes hung 20∘ from the vertical. Into which of the fol

iogann1982 [59]

The following intervals would you expect T(tension) to fall : <u>2000 to 4000 N </u>

<h3>Further explanation</h3>

The force acting on a system with static equilibrium is 0

$\large{\boxed{\bold{\sum F=0}}$

(forces acting as translational motion only, not including rotational forces)

$\displaystyle \sum F_x = 0\\\\ \sum F_y = 0$

We complete the questions:

A 20-kg loudspeaker is suspended 2.0 m below the ceiling by two ropes that are each 30? from vertical.

Find the value of T, the magnitude of the tension in either of the ropes.

Express your answer in newtons.

Suppose that the loudspeaker in the problem has a mass of 500 kg and the ropes hung 20? from the vertical. Into which of the following intervals would you expect T to fall? You don't have to calculate Texactly to answer this question; just make an estimate.

500 to 1000 N

1000 to 2000 N

2000 to 4000 N

4000 to 8000 N

8000 to 16,000 N

In a 500-kg loudspeaker system and two ropes that are each 20° from vertical, we see the forces acting on the y axis (vertical)

$\displaystyle \sum F_y = 0\\\\T1_y+T2_y-w=0\\\\T1~cos~20^o+T2~cos~20^o=m\times g$

we assume g = 10 m/s², then :

$\displaystyle 2T~cos~20=500\times 10\\\\T~cos~20=2500\\\\\boxed{\bold{T=26592 N}}}$

So the value of T is between 2000 and 4000 N

<h3>Learn more</h3>

Newton's Law

brainly.com/question/13725525

Keywords : the loudspeaker, ropes, Tension, mass, intervals

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3 years ago

If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?

sdas [7]

Data:
$f_{2} = 42 Hz$
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
$f_{n} = \frac{nV}{2L}$

Wire 2 → 2º Harmonic → n = 2

$f_{n} = \frac{nV}{2L}$
$f_{2} = \frac{2V}{2L} 
$
$2V = f_{2} *2L$
$V = \frac{ f_{2}*2L }{2}$
$V = \frac{42*2L}{2}$
$V = \frac{84L}{2}$
$V = 42L$

Wire 1 → 1º Harmonic or Fundamental rope → n = 1

$f_{n} = \frac{nV}{2L}$
$f_{1} = \frac{1V}{2L}$
$f_{1} = \frac{V}{2L}$

If, We have:
V = 42L
Soon:
$f_{1} = \frac{V}{2L}$
$f_{1} = \frac{42L}{2L}$
$\boxed{f_{1} = 21 Hz}$

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0

3 years ago

Read 2 more answers