Question

At what temperature (in °C )would the volume of a gas be equal to 45.7 L, if the volume of that gas was 33.9 L at 12.4 ° C

Answer 1

The volume of 45.7L will be at temperature 16.72°C

Explanation:

Given:

Volume, V₁ = 45.7L

V₂ = 33.9L

Temperature, T₂ = 12.4°C

T₁ = ?

According to the Charle's law:

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

Substituting the value we get:

$\frac{45.7}{T_1} = \frac{33.9}{12.4}\\\\T_1 = \frac{45.7 X 12.4}{33.9} \\\\T_1 = 16.72^oC$

Therefore, the volume of 45.7L will be at temperature 16.72°C