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Lady bird [3.3K]
3 years ago
12

The area of a triangle is 22in and it’s base is 2, what is the length of its height

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

  22 in

Step-by-step explanation:

The formula for area is ...

  A = 1/2bh

Filling in the given values, we have ...

  22 = 1/2(2)h

  22 = h . . . . simplify

The height is 22 inches.

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Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

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Answer:

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Step-by-step explanation:

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