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tino4ka555 [31]
2 years ago
7

Annual precipitation rates can be collected for several years, added together, and divided by the number of years to obtain an a

verage annual precipitation rate. Lesson 1. 01 Question 2 options: True False.
Chemistry
1 answer:
Art [367]2 years ago
6 0

The average annual precipitation has been calculated by dividing the sum of average rainfall to the number of years. Thus, the given statement is true.

Precipitation has been given as the amount of water in the atmosphere that has been to fall off on the earth.

<h3 /><h3>Average Annual Precipitation</h3>

The average has been defined as the mid-value for the number readings. The average precipitation has been the approximate fall of water on the earth in the specified period.

The average annual precipitation has been calculated with the ratio of the sum of the average rainfall in the number of years to the total number of years. Thus, the given statement is true.

Learn more about precipitation, here:

brainly.com/question/5019199

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Different isotopes of the same element must have a different
slega [8]

Answer:

they must have same atomic number and different atomic mass

6 0
2 years ago
The red line of the hydrogen emission spectrum has a wavelength of 656.1 nm. Calculate the energy of one photon
Effectus [21]

The formula we can use here is the Plancks equation:

E = h c / ʎ

where h is Plancks constant = 6.626 × 10-34 m2 kg / s, c is speed of light = 3 x 10^8 m/s and ʎ is wavelength = 656.1 x 10^-9 m

 

Therefore E is:

E = (6.626 × 10-34 m2 kg / s) * (3 x 10^8 m/s) / 656.1 x 10^-9 m

<span>E = 3.03 x 10^-19 J</span>

4 0
3 years ago
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
324.55 cm - (6104.5 cm²/22.3 cm)
Ganezh [65]

Answer: 50.806 cm is the correct answer.

Explanation: First divide 6104.5 cm^2 by 22.3 cm.

\frac{6104.5cm^2}{22.3cm} = 273.74 cm

*Note: When dividing units, subtract the exponents, and when multiplying units simply add the exponents.

Then continue by subtracting 324.55 cm - 273.74 cm.

This should give you an answer of 50.806 cm.

3 0
1 year ago
Hydrogen ions cannot exist alone but they exist after combining with water molecules true or false​
juin [17]
True because hydrogen ions combines with h2o to make hydronium ion, so in a sense h2o is acting like a base.
4 0
3 years ago
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