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tino4ka555 [31]
2 years ago
7

Annual precipitation rates can be collected for several years, added together, and divided by the number of years to obtain an a

verage annual precipitation rate. Lesson 1. 01 Question 2 options: True False.
Chemistry
1 answer:
Art [367]2 years ago
6 0

The average annual precipitation has been calculated by dividing the sum of average rainfall to the number of years. Thus, the given statement is true.

Precipitation has been given as the amount of water in the atmosphere that has been to fall off on the earth.

<h3 /><h3>Average Annual Precipitation</h3>

The average has been defined as the mid-value for the number readings. The average precipitation has been the approximate fall of water on the earth in the specified period.

The average annual precipitation has been calculated with the ratio of the sum of the average rainfall in the number of years to the total number of years. Thus, the given statement is true.

Learn more about precipitation, here:

brainly.com/question/5019199

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Relate dark matter to the development of the universe after the Big Bang. In 3-5 sentences, speculate on how the development of
Alenkinab [10]

Answer:

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3 years ago
ANSWER AS SOON AS POSSIBLE PLEASE!!!! Which type of water represents the largest percentage of earths water?
antoniya [11.8K]

Answer:

im pretty sure its groundwater just read this and see the answer

Explanation:

The ocean holds about 97 percent of the Earth's water; the remaining three percent is found in glaciers and ice, below the ground, in rivers and lakes. Of the world's total water supply of about 332 million cubic miles of water, about 97 percent is found in the ocean.

5 0
2 years ago
Read 2 more answers
Consider the titration of 1L of 0.36 M NH3 (Kb=1.8x10−5) with 0.74 M HCl. What is the pH at the equivalence point of the titrati
worty [1.4K]

Answer:

C

Explanation:

The question asks to calculate the pH at equivalence point of the titration between ammonia and hydrochloric acid

Firstly, we write the equation of reaction between ammonia and hydrochloric acid.

NH3(aq)+HCl(aq)→NH4Cl(aq)

Ionically:

HCl + NH3 ---> NH4  +  Cl-

Firstly, we calculate the number of moles of  the ammonia  as follows:

from c = n/v and thus, n = cv = 0.36 × 1 = 0.36 moles

At the equivalence point, there is equal number of moles of ammonia and HCl.

Hence, volume of HCl = number of moles/molarity of HCl = 0.36/0.74 = 0.486L

Hence, the total volume of solution will be 1 + 0.486 = 1.486L

Now, we calculate the concentration of the ammonium ions = 0.36/1.486 = 0.242M

An ICE TABLE IS USED TO FIND THE CONCENTRATION OF THE HYDROXONIUM ION(H3O+). ICE STANDS FOR INITIAL, CHANGE AND EQUILIBRIUM.

                 NH4+      H2O     ⇄  NH3        H3O+

I                0.242                           0             0

C                 -X                              +x              +X

E             0.242-X                          X              X

Since the question provides us with the base dissociation constant value K b, we can calculate the acid dissociation constant value Ka

To find this, we use the mathematical equation below

K a ⋅ K b    = K w

 

, where  K w- the self-ionization constant of water, equal to  

10 ^-14  at room temperature

This means that you have

K a = K w.K b   = 10 ^− 14 /1.8 * 10^-5 =  5.56 * 10^-10

Ka = [NH3][H3O+]/[NH4+]

= x * x/(0.242-x)

Since the value of Ka is small, we can say that 0.242-x ≈  0.242

Hence, K a = x^2/0.242 = 5.56 * 10^-10

x^2 = 0.242 * 5.56 * 10^-10 = 1.35 * 10^-10

x = 0.00001161895

[H3O+] = 0.00001161895

pH = -log[H3O+]

pH = -log[0.00001161895 ] = 4.94

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MaRussiya [10]

Answer:

17.6 grams of nitrogen gas

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