Answer:
The range would you expect 99.00 percent of the grades is 44.2 to 95.8
Step-by-step explanation:
In order to calculate the range would you expect 99.00 percent of the grades we would have to make the following calculation:
range would you expect 99.00 percent of the grades=mean ± 2.58* standard deviation
According to the given data we have the following:
mean=70
standard deviation=10
Therefore, range would you expect 99.00 percent of the grades= 70± 2.58*10
=70 - 2.58*10 to 70 + 2.58*10
Therefore, range would you expect 99.00 percent of the grades=44.2 to 95.8.
Answer:
u can use the hit and trial method for this
2x^2 + 9x + 4 = 0
x^2 + 9/2*x + 2 = 0
x = - 9/4 +- √(81/16 - 32/16) = - 9/4 +- 7/4
x1 = - 1/2
x2 = - 4
There would be 3 even numbers on a six sided dice. So, 3 / 6 = .50, or 50%
Answer:
2.953
Step-by-step explanation:
Following the order of operations, work from left to right for addition/subtraction.
Subtraction:
![\begin{array}{r r r r r} ^0\diagup\!\!\!\!1 &. & ^10 & ^0\diagup\!\!\!\!1&^1 2\\ -\quad0&.&8&0&9\\\cline{1-5}0&.&2&0&3\\\cline{1-5} \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Br%20r%20r%20r%20r%7D%20%5E0%5Cdiagup%5C%21%5C%21%5C%21%5C%211%20%26.%20%26%20%5E10%20%26%20%5E0%5Cdiagup%5C%21%5C%21%5C%21%5C%211%26%5E1%202%5C%5C%20-%5Cquad0%26.%268%260%269%5C%5C%5Ccline%7B1-5%7D0%26.%262%260%263%5C%5C%5Ccline%7B1-5%7D%20%5Cend%7Baligned%7D)
Addition:
![\begin{array}{r c c c r} 0 & . & 2&0&3\\ + \:\:2 &.& 7 & 5\\\cline{1-5}2&.&9&5&3\\\cline{1-5} \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Br%20c%20c%20c%20r%7D%200%20%26%20.%20%26%202%260%263%5C%5C%20%2B%20%5C%3A%5C%3A2%20%26.%26%207%20%26%205%5C%5C%5Ccline%7B1-5%7D2%26.%269%265%263%5C%5C%5Ccline%7B1-5%7D%20%5Cend%7Baligned%7D)
Therefore, the solution is 2.953