1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BabaBlast [244]
3 years ago
13

Evaluate y = 9 * (5/2)^x for x = -3.

Mathematics
1 answer:
dem82 [27]3 years ago
6 0
You can find your answer by just substituting -3 for x......
You might be interested in
Solve the equation<br> 12 + 0.35x = 20.05
zubka84 [21]
X=23 First, you have to subtract 12 by 12 to cancel it out. Next, you have to do the same thing to 20.05. 20.05 minus 12 is 8.05. All you have left is .35x. To get rid of the this you have to divide .35x by .35. Now all you have left is x. Finally you have to do the same thing to 8.05. 8.05 divided by .35 is 23. So, x=23
7 0
3 years ago
Read 2 more answers
Particle P moves along the y-axis so that its position at time t is given by y(t)=4t−23 for all times t. A second particle, part
sergey [27]

a) The limit of the position of particle Q when time approaches 2 is -\pi.

b) The velocity of particle Q is v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}} for all t \ne 2.

c) The rate of change of the distance between particle P and particle Q at time t = \frac{1}{2} is \frac{4\sqrt{82}}{9}.

<h3>How to apply limits and derivatives to the study of particle motion</h3>

a) To determine the limit for t = 2, we need to apply the following two <em>algebraic</em> substitutions:

u = \pi t (1)

k = 2\pi - u (2)

Then, the limit is written as follows:

x(t) =  \lim_{t \to 2} \frac{\sin \pi t}{2-t}

x(t) =  \lim_{t \to 2} \frac{\pi\cdot \sin \pi t}{2\pi - \pi t}

x(u) =  \lim_{u \to 2\pi} \frac{\pi\cdot \sin u}{2\pi - u}

x(k) =  \lim_{k \to 0} \frac{\pi\cdot \sin (2\pi-k)}{k}

x(k) =  -\pi\cdot  \lim_{k \to 0} \frac{\sin k}{k}

x(k) = -\pi

The limit of the position of particle Q when time approaches 2 is -\pi. \blacksquare

b) The function velocity of particle Q is determined by the <em>derivative</em> formula for the division between two functions, that is:

v_{Q}(t) = \frac{f'(t)\cdot g(t)-f(t)\cdot g'(t)}{g(t)^{2}} (3)

Where:

  • f(t) - Function numerator.
  • g(t) - Function denominator.
  • f'(t) - First derivative of the function numerator.
  • g'(x) - First derivative of the function denominator.

If we know that f(t) = \sin \pi t, g(t) = 2 - t, f'(t) = \pi \cdot \cos \pi t and g'(x) = -1, then the function velocity of the particle is:

v_{Q}(t) = \frac{\pi \cdot \cos \pi t \cdot (2-t)-\sin \pi t}{(2-t)^{2}}

v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}}

The velocity of particle Q is v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}} for all t \ne 2. \blacksquare

c) The vector <em>rate of change</em> of the distance between particle P and particle Q (\dot r_{Q/P} (t)) is equal to the <em>vectorial</em> difference between respective vectors <em>velocity</em>:

\dot r_{Q/P}(t) = \vec v_{Q}(t) - \vec v_{P}(t) (4)

Where \vec v_{P}(t) is the vector <em>velocity</em> of particle P.

If we know that \vec v_{P}(t) = (0, 4), \vec v_{Q}(t) = \left(\frac{2\pi\cdot \cos \pi t - \pi\cdot t \cdot \cos \pi t + \sin \pi t}{(2-t)^{2}}, 0 \right) and t = \frac{1}{2}, then the vector rate of change of the distance between the two particles:

\dot r_{P/Q}(t) = \left(\frac{2\pi \cdot \cos \pi t - \pi\cdot t \cdot \cos \pi t + \sin \pi t}{(2-t)^{2}}, -4 \right)

\dot r_{Q/P}\left(\frac{1}{2} \right) = \left(\frac{2\pi\cdot \cos \frac{\pi}{2}-\frac{\pi}{2}\cdot \cos \frac{\pi}{2} +\sin \frac{\pi}{2}}{\frac{3}{2} ^{2}}, -4 \right)

\dot r_{Q/P} \left(\frac{1}{2} \right) = \left(\frac{4}{9}, -4 \right)

The magnitude of the vector <em>rate of change</em> is determined by Pythagorean theorem:

|\dot r_{Q/P}| = \sqrt{\left(\frac{4}{9} \right)^{2}+(-4)^{2}}

|\dot r_{Q/P}| = \frac{4\sqrt{82}}{9}

The rate of change of the distance between particle P and particle Q at time t = \frac{1}{2} is \frac{4\sqrt{82}}{9}. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted. Correct form is shown below:

<em>Particle </em>P<em> moves along the y-axis so that its position at time </em>t<em> is given by </em>y(t) = 4\cdot t - 23<em> for all times </em>t<em>. A second particle, </em>Q<em>, moves along the x-axis so that its position at time </em>t<em> is given by </em>x(t) = \frac{\sin \pi t}{2-t}<em> for all times </em>t \ne 2<em>. </em>

<em />

<em>a)</em><em> As times approaches 2, what is the limit of the position of particle </em>Q?<em> Show the work that leads to your answer. </em>

<em />

<em>b) </em><em>Show that the velocity of particle </em>Q<em> is given by </em>v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t +\sin \pi t}{(2-t)^{2}}<em>.</em>

<em />

<em>c)</em><em> Find the rate of change of the distance between particle </em>P<em> and particle </em>Q<em> at time </em>t = \frac{1}{2}<em>. Show the work that leads to your answer.</em>

To learn more on derivatives, we kindly invite to check this verified question: brainly.com/question/2788760

3 0
2 years ago
HELP
Mrrafil [7]
Answer: 3 years

Because:
1 year=1050
2years=525
3years=262.5
5 0
3 years ago
Find an equation of the line that goes through the points (-9,-20) and (-8,-17). Write your answer in the form y = m x + b .
Oliga [24]

Answer:

y = 3x + 7

Step-by-step explanation:

First, we will solve for the slope (m).

The formula for slope is: m = \frac{y2 - y1}{x2 - x1}

m = \frac{-17 - -20}{-8 - -9} --- enter the points into the formula

m = \frac{3}{1} --- simplify

m = 3 --- simplify

Now we will solve for the y-intercept (b).

y = mx + b

y = 3x + b --- substitute the slope into the equation

-20 = 3(-9) + b --- substitute the x and y of either point into the equation

-20 = -27 + b --- simplify

7 = b --- add 27 to both sides

b = 7

Done.

y = 3x + 7

4 0
3 years ago
A square 20 cm long and a
Gemiola [76]

Answer:

20 * 4 = 80

Step-by-step explanation:

the answer is 80 cuz you have to multiply 20 ( the square) by 4 ( the number of sides) and you get 80

4 0
2 years ago
Other questions:
  • If it is 3:55 what time would it be and a hour and a half later
    7·2 answers
  • What is an equation of the line that passes through the points (5,4) and (2,-2)
    12·1 answer
  • On average a fifth grader blinks 15 times per minute. About how many times will a fifth grader blink in a day?
    7·2 answers
  • Thee vertex of a parabola is (-5,2), and its focus is (-1,2). What is the standard form of the parabola?​
    10·2 answers
  • WILL MARK BRAINLIEST!!
    15·1 answer
  • WHATS THE MEASURE OF THE ANGLE INDICATED?<br> GEOMETRY/PLS HELP/GOD BLESS
    8·1 answer
  • Represent each of these temperatures in degrees Fahrenheit with a positive or negative number.
    10·1 answer
  • ANSWER ASAP I WILL MAKE BRAINLYIST
    14·2 answers
  • Identify the variables: 8c * 7c - 10p + 12
    6·1 answer
  • Identify the x- and y-intercepts.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!