Answer:
Angle of diffraction for second order maxima is θ = 18.941°
Explanation:
From the question it is given that
wavelength of incident light = λ = 541 nm = 541 x
order of maxima = n =2
diffraction grating has 600 lines per mm
⇒ distance between two slit is = 1.66 x
m
using the relation of Braggs diffraction formula i.e.,
2dsinθ = nλ ..................................(1)
where, d = distance between two lines of grating
θ is the angle of diffraction
n= order of maxima
λ is the intensity of incident photon
on substituting the respected values in relation (1) we get,
2 x 1.66 x m sinθ = 2 x 541 x
⇒ sinθ = 0.3246
⇒ θ = = 18.941 °