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marta [7]
3 years ago
8

g When a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A. What is the resistance

of the glowing thin-filament bulb
Physics
1 answer:
larisa [96]3 years ago
5 0

Answer:

R = 42.67 ohms

Explanation:

It is given that, a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A.

It means that when two batteries are connected in series, then the total voltage is 3.2 volts

Let R is the resistance of the glowing thin-filament bulb. So, using Ohm's law we get :

V=IR\\\\R=\dfrac{V}{I}

So,

R=\dfrac{3.2}{0.075}\\\\R=42.67\ \Omega

So, the resistance of the bulb is 42.67 ohms.

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