Question

g When a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A. What is the resistance of the glowing thin-filament bulb

Answer 1

Answer:

R = 42.67 ohms

Explanation:

It is given that, a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A.

It means that when two batteries are connected in series, then the total voltage is 3.2 volts

Let R is the resistance of the glowing thin-filament bulb. So, using Ohm's law we get :

$V=IR\\\\R=\dfrac{V}{I}$

So,

$R=\dfrac{3.2}{0.075}\\\\R=42.67\ \Omega$

So, the resistance of the bulb is 42.67 ohms.